Solution to problem 17 in Julia
This commit is contained in:
parent
1b7c9a9c98
commit
22589584c7
65
src/Julia/Problem017.jl
Normal file
65
src/Julia/Problem017.jl
Normal file
@ -0,0 +1,65 @@
|
||||
#=
|
||||
Created on 28 Jul 2021
|
||||
|
||||
@author: David Doblas Jiménez
|
||||
@email: daviddoji@pm.me
|
||||
|
||||
Solution for Problem 17 of Project Euler
|
||||
https://projecteuler.net/problem=17
|
||||
=#
|
||||
|
||||
function num2letters(num)
|
||||
nums = Dict(
|
||||
0 => "", 1 => "one", 2 => "two", 3 => "three", 4 => "four", 5 => "five",
|
||||
6 => "six", 7 => "seven", 8 => "eight", 9 => "nine", 10 => "ten",
|
||||
11 => "eleven", 12 => "twelve", 13 => "thirteen", 14 => "fourteen",
|
||||
15 => "fifteen", 16 => "sixteen", 17 => "seventeen", 18 => "eighteen",
|
||||
19 => "nineteen", 20 => "twenty", 30 => "thirty", 40 => "forty",
|
||||
50 => "fifty", 60 => "sixty", 70 => "seventy", 80 => "eighty",
|
||||
90 => "ninety", 100 => "hundred", 1000 => "thousand"
|
||||
)
|
||||
|
||||
if num <= 20
|
||||
return length(nums[num])
|
||||
elseif num < 100
|
||||
tens, units = divrem(num, 10)
|
||||
return length(nums[tens * 10]) + num2letters(units)
|
||||
elseif num < 1000
|
||||
hundreds, rest = divrem(num, 100)
|
||||
if rest != 0
|
||||
return num2letters(hundreds) + length(nums[100]) + length("and") + num2letters(rest)
|
||||
else
|
||||
return num2letters(hundreds) + length(nums[100])
|
||||
end
|
||||
else
|
||||
thousands, rest = divrem(num, 1000)
|
||||
return num2letters(thousands) + length(nums[1000])
|
||||
end
|
||||
end
|
||||
|
||||
function Problem17()
|
||||
#=
|
||||
If the numbers 1 to 5 are written out in words: one, two, three, four,
|
||||
five, then there are 3 + 3 + 5 + 4 + 4 = 19 letters used in total.
|
||||
|
||||
If all the numbers from 1 to 1000 (one thousand) inclusive were written
|
||||
out in words, how many letters would be used?
|
||||
|
||||
NOTE: Do not count spaces or hyphens. For example, 342 (three hundred and
|
||||
forty-two) contains 23 letters and 115 (one hundred and fifteen) contains
|
||||
20 letters. The use of "and" when writing out numbers is in compliance
|
||||
with British usage.
|
||||
=#
|
||||
n = 1000
|
||||
letters = 0
|
||||
for num in 1:n
|
||||
letters += num2letters(num)
|
||||
end
|
||||
return letters
|
||||
end
|
||||
|
||||
|
||||
println("Time to evaluate Problem 17:")
|
||||
@time Problem17()
|
||||
println("")
|
||||
println("Result for Problem 17: ", Problem17())
|
Loading…
x
Reference in New Issue
Block a user