Solution to problem 17
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src/Python/Problem017.py
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src/Python/Problem017.py
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#!/usr/bin/env python3
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"""
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Created on 13 Jan 2018
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@author: David Doblas Jiménez
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@email: daviddoji@pm.me
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Solution for problem 17 of Project Euler
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https://projecteuler.net/problem=17
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"""
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from utils import timeit
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def num2letters(num):
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nums = {0: '', 1: 'one', 2: 'two', 3: 'three', 4: 'four', 5: 'five',
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6: 'six', 7: 'seven', 8: 'eight', 9: 'nine', 10: 'ten',
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11: 'eleven', 12: 'twelve', 13: 'thirteen', 14: 'fourteen',
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15: 'fifteen', 16: 'sixteen', 17: 'seventeen', 18: 'eighteen',
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19: 'nineteen', 20: 'twenty', 30: 'thirty', 40: 'forty',
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50: 'fifty', 60: 'sixty', 70: 'seventy', 80: 'eighty',
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90: 'ninety', 100: 'hundred', 1000: 'thousand'}
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if num <= 20:
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return len(nums[num])
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elif num < 100:
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tens, units = divmod(num, 10)
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return len(nums[tens * 10]) + num2letters(units)
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elif num < 1000:
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hundreds, rest = divmod(num, 100)
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if rest:
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return num2letters(hundreds) + len(nums[100]) + len('and') +\
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num2letters(rest)
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else:
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return num2letters(hundreds) + len(nums[100])
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else:
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thousands, rest = divmod(num, 1000)
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return num2letters(thousands) + len(nums[1000])
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@timeit("Problem 17")
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def compute():
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"""
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If the numbers 1 to 5 are written out in words: one, two, three, four,
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five, then there are 3 + 3 + 5 + 4 + 4 = 19 letters used in total.
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If all the numbers from 1 to 1000 (one thousand) inclusive were written
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out in words, how many letters would be used?
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NOTE: Do not count spaces or hyphens. For example, 342 (three hundred and
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forty-two) contains 23 letters and 115 (one hundred and fifteen) contains
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20 letters. The use of "and" when writing out numbers is in compliance
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with British usage.
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"""
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n = 1000
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letters = 0
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for num in range(1, n + 1):
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letters += num2letters(num)
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return letters
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if __name__ == "__main__":
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print(f"Result for Problem 17: {compute()}")
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