Solution to problem 17

This commit is contained in:
David Doblas Jiménez 2021-07-28 20:38:03 +02:00
parent 7f6ea29f1a
commit 1b7c9a9c98

62
src/Python/Problem017.py Normal file
View File

@ -0,0 +1,62 @@
#!/usr/bin/env python3
"""
Created on 13 Jan 2018
@author: David Doblas Jiménez
@email: daviddoji@pm.me
Solution for problem 17 of Project Euler
https://projecteuler.net/problem=17
"""
from utils import timeit
def num2letters(num):
nums = {0: '', 1: 'one', 2: 'two', 3: 'three', 4: 'four', 5: 'five',
6: 'six', 7: 'seven', 8: 'eight', 9: 'nine', 10: 'ten',
11: 'eleven', 12: 'twelve', 13: 'thirteen', 14: 'fourteen',
15: 'fifteen', 16: 'sixteen', 17: 'seventeen', 18: 'eighteen',
19: 'nineteen', 20: 'twenty', 30: 'thirty', 40: 'forty',
50: 'fifty', 60: 'sixty', 70: 'seventy', 80: 'eighty',
90: 'ninety', 100: 'hundred', 1000: 'thousand'}
if num <= 20:
return len(nums[num])
elif num < 100:
tens, units = divmod(num, 10)
return len(nums[tens * 10]) + num2letters(units)
elif num < 1000:
hundreds, rest = divmod(num, 100)
if rest:
return num2letters(hundreds) + len(nums[100]) + len('and') +\
num2letters(rest)
else:
return num2letters(hundreds) + len(nums[100])
else:
thousands, rest = divmod(num, 1000)
return num2letters(thousands) + len(nums[1000])
@timeit("Problem 17")
def compute():
"""
If the numbers 1 to 5 are written out in words: one, two, three, four,
five, then there are 3 + 3 + 5 + 4 + 4 = 19 letters used in total.
If all the numbers from 1 to 1000 (one thousand) inclusive were written
out in words, how many letters would be used?
NOTE: Do not count spaces or hyphens. For example, 342 (three hundred and
forty-two) contains 23 letters and 115 (one hundred and fifteen) contains
20 letters. The use of "and" when writing out numbers is in compliance
with British usage.
"""
n = 1000
letters = 0
for num in range(1, n + 1):
letters += num2letters(num)
return letters
if __name__ == "__main__":
print(f"Result for Problem 17: {compute()}")