56 lines
1.6 KiB
Julia
56 lines
1.6 KiB
Julia
#=
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Created on 01 Aug 2021
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@author: David Doblas Jiménez
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@email: daviddoji@pm.me
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Solution for Problem 18 of Project Euler
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https://projecteuler.net/problem=18 =#
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function Problem18()
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#=
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By starting at the top of the triangle below and moving to adjacent
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numbers on the row below, the maximum total from top to bottom is 23.
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3
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7 4
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2 4 6
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8 5 9 3
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That is, 3 + 7 + 4 + 9 = 23.
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Find the maximum total from top to bottom of the triangle above =#
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triangle = [ # Mutable
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[75],
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[95,64],
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[17,47,82],
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[18,35,87,10],
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[20, 4,82,47,65],
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[19, 1,23,75, 3,34],
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[88, 2,77,73, 7,63,67],
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[99,65, 4,28, 6,16,70,92],
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[41,41,26,56,83,40,80,70,33],
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[41,48,72,33,47,32,37,16,94,29],
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[53,71,44,65,25,43,91,52,97,51,14],
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[70,11,33,28,77,73,17,78,39,68,17,57],
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[91,71,52,38,17,14,91,43,58,50,27,29,48],
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[63,66, 4,68,89,53,67,30,73,16,69,87,40,31],
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[4,62,98,27,23, 9,70,98,73,93,38,53,60, 4,23],
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]
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len_triangle = length(triangle)
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for i in len_triangle - 1:-1:1
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for j in 1:length(triangle[i])
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triangle[i][j] += max(triangle[i + 1][j], triangle[i + 1][j + 1])
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end
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end
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return triangle[1][1]
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end
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println("Time to evaluate Problem 18:")
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@time Problem18()
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println("")
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println("Result for Problem 18: ", Problem18())
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