Solution to problem 33 in Julia

src/Julia/Problem033.jl

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+#=
+Created on 01 Sep 2021
+
+@author: David Doblas Jiménez
+@email: daviddoji@pm.me
+
+Solution for Problem 33 of Project Euler
+https://projecteuler.net/problem=33
+=#
+
+using BenchmarkTools
+
+function Problem33()
+    #=
+    The fraction 49/98 is a curious fraction, as an inexperienced mathematician
+    in attempting to simplify it may incorrectly believe that 49/98 = 4/8,
+    which is correct, is obtained by cancelling the 9s.
+
+    We shall consider fractions like, 30/50 = 3/5, to be trivial examples.
+
+    There are exactly four non-trivial examples of this type of fraction, less
+    than one in value, and containing two digits in the numerator and denominator.
+
+    If the product of these four fractions is given in its lowest common terms,
+    find the value of the denominator.
+    =#
+    numerator = 1
+    denominator = 1
+    for x in 10:99
+        for y in 10:99
+            if x < y
+                if reverse(digits(x))[2] == reverse(digits(y))[1]
+                    if reverse(digits(y))[2] != 0
+                        if reverse(digits(x))[1] / reverse(digits(y))[2] == x / y
+                            numerator *= x
+                            denominator *= y
+                        end
+                    end
+                end
+            end
+        end
+    end
+
+    return Int(denominator/numerator)
+end
+
+
+println("Time to evaluate Problem 33:")
+@btime Problem33()
+println("")
+println("Result for Problem 33: ", Problem33())