Solution to problem 33

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David Doblas Jiménez 2021-09-01 10:44:25 +02:00
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#!/usr/bin/env python3
"""
Created on 04 Mar 2021
@author: David Doblas Jiménez
@email: daviddoji@pm.me
Solution for problem 33 of Project Euler
https://projecteuler.net/problem=33
"""
from utils import timeit
@timeit("Problem 33")
def compute():
"""
The fraction 49/98 is a curious fraction, as an inexperienced mathematician
in attempting to simplify it may incorrectly believe that 49/98 = 4/8,
which is correct, is obtained by cancelling the 9s.
We shall consider fractions like, 30/50 = 3/5, to be trivial examples.
There are exactly four non-trivial examples of this type of fraction, less
than one in value, and containing two digits in the numerator and denominator.
If the product of these four fractions is given in its lowest common terms,
find the value of the denominator.
"""
numerator = 1
denominator = 1
for x in range(10, 100):
for y in range(10, 100):
if x < y:
if str(x)[1] == str(y)[0]:
if int(str(y)[1]) != 0:
if int(str(x)[0]) / int(str(y)[1]) == x / y:
numerator *= x
denominator *= y
return int(denominator/numerator)
if __name__ == "__main__":
print(f"Result for Problem 33: {compute()}")