Solution to problem 6 in Julia

src/Julia/Problem006.jl

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+#=
+Created on 20 Jun 2021
+
+@author: David Doblas Jiménez
+@email: daviddoji@pm.me
+
+Solution for Problem 6 of Project Euler
+https://projecteuler.net/problem=6
+=#
+
+function Problem6()
+    #=
+    The sum of the squares of the first ten natural numbers is,
+    1^2 + 2^2 + ... + 10^2 = 385
+
+    The square of the sum of the first ten natural numbers is,
+    (1 + 2 + ... + 10)^2 = 55^2 = 3025
+
+    Hence the difference between the sum of the squares of the first ten
+    natural numbers and the square of the sum is 3025 − 385 = 2640.
+
+    Find the difference between the sum of the squares of the first one
+    hundred natural numbers and the square of the sum. Statement
+    =#
+    n = 100
+    square_of_sum = sum(i for i in (1:n))^2
+    sum_squares = sum(i^2 for i in 1:n)
+    diff = square_of_sum - sum_squares
+    return diff
+end
+
+
+println("Time to evaluate Problem 6:")
+@time Problem6()
+println("")
+println("Result for Problem 6: ", Problem6())