Solution to problem 5 in Julia

src/Julia/Problem005.jl

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+#=
+Created on 20 Jun 2021
+
+@author: David Doblas Jiménez
+@email: daviddoji@pm.me
+
+Solution for Problem 5 of Project Euler
+https://projecteuler.net/problem=5
+=#
+
+#=
+The LCM of two natural numbers x and y is given by:
+def lcm(x, y):
+    return x * y // math.gcd(x, y)
+
+It is possible to compute the LCM of more than two numbers by iteratively
+computing the LCM of two numbers, i.e. LCM(a, b, c) = LCM(a, LCM(b, c))
+=#
+
+
+function Problem5()
+    #=
+    2520 is the smallest number that can be divided by each of the numbers
+    from 1 to 10 without any remainder.
+
+    What is the smallest positive number that is evenly divisible by all of
+    the numbers from 1 to 20?
+    =#
+    ans = 1
+    for i in 1:21
+        ans *= i ÷ gcd(i, ans)
+    end
+
+    return ans
+end
+
+
+println("Time to evaluate Problem 5:")
+@time Problem5()
+println("")
+println("Result for Problem 5: ", Problem5())