Solution to problem 33

src/Python/Problem033.py

@@ -0,0 +1,47 @@
+#!/usr/bin/env python3
+"""
+Created on 04 Mar 2021
+
+@author: David Doblas Jiménez
+@email: daviddoji@pm.me
+
+Solution for problem 33 of Project Euler
+https://projecteuler.net/problem=33
+"""
+
+from utils import timeit
+
+
+@timeit("Problem 33")
+
+def compute():
+    """
+    The fraction 49/98 is a curious fraction, as an inexperienced mathematician
+    in attempting to simplify it may incorrectly believe that 49/98 = 4/8,
+    which is correct, is obtained by cancelling the 9s.
+
+    We shall consider fractions like, 30/50 = 3/5, to be trivial examples.
+
+    There are exactly four non-trivial examples of this type of fraction, less
+    than one in value, and containing two digits in the numerator and denominator.
+
+    If the product of these four fractions is given in its lowest common terms,
+    find the value of the denominator.
+    """
+    numerator = 1
+    denominator = 1
+    for x in range(10, 100):
+        for y in range(10, 100):
+            if x < y:
+                if str(x)[1] == str(y)[0]:
+                    if int(str(y)[1]) != 0:
+                        if int(str(x)[0]) / int(str(y)[1]) == x / y:
+                            numerator *= x
+                            denominator *= y
+    
+    return int(denominator/numerator)
+
+
+if __name__ == "__main__":
+
+    print(f"Result for Problem 33: {compute()}")