Typo again (grrr)
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@@ -958,9 +958,6 @@ the rows which only contain integers and which sum to n. (★★★)</p>
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<li><p class="first">Compute bootstrapped 95% confidence intervals for the mean of a 1D array X
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(i.e., resample the elements of an array with replacement N times, compute
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the mean of each sample, and then compute percentiles over the means). (★★★)</p>
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</li>
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</ol>
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<blockquote>
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<pre class="code python literal-block">
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<span class="comment single"># Author: Jessica B. Hamrick</span>
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@@ -971,7 +968,8 @@ the mean of each sample, and then compute percentiles over the means). (★★
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<span class="name">confint</span> <span class="operator">=</span> <span class="name">np</span><span class="operator">.</span><span class="name">percentile</span><span class="punctuation">(</span><span class="name">means</span><span class="punctuation">,</span> <span class="punctuation">[</span><span class="literal number float">2.5</span><span class="punctuation">,</span> <span class="literal number float">97.5</span><span class="punctuation">])</span>
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<span class="keyword">print</span><span class="punctuation">(</span><span class="name">confint</span><span class="punctuation">)</span>
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</pre>
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</blockquote>
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</li>
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</ol>
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</div>
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</body>
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</html>
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16
README.rst
16
README.rst
@@ -1118,13 +1118,13 @@ Thanks to Michiaki Ariga, there is now a
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(i.e., resample the elements of an array with replacement N times, compute
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the mean of each sample, and then compute percentiles over the means). (★★★)
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.. code-block:: python
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.. code-block:: python
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# Author: Jessica B. Hamrick
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# Author: Jessica B. Hamrick
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X = np.random.randn(100) # random 1D array
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N = 1000 # number of bootstrap samples
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idx = np.random.randint(0, X.size, (N, X.size))
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means = X[idx].mean(axis=1)
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confint = np.percentile(means, [2.5, 97.5])
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print(confint)
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X = np.random.randn(100) # random 1D array
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N = 1000 # number of bootstrap samples
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idx = np.random.randint(0, X.size, (N, X.size))
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means = X[idx].mean(axis=1)
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confint = np.percentile(means, [2.5, 97.5])
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print(confint)
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