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3
10.sql
3
10.sql
@@ -4,5 +4,6 @@ SELECT d."name", e."per_pupil_expenditure"
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FROM "expenditures" AS e
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JOIN "districts" AS d
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ON e."district_id" = d."id"
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ORDER BY "per_pupil_expenditure" DESC
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WHERE d."type" = 'Public School District'
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ORDER BY e."per_pupil_expenditure" DESC
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LIMIT 10;
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14
11.sql
14
11.sql
@@ -0,0 +1,14 @@
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-- write a SQL query to display the names of schools, their per-pupil expenditure, and their graduation rate.
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-- Sort the schools from greatest per-pupil expenditure to least.
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-- If two schools have the same per-pupil expenditure, sort by school name.
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--
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-- You should assume a school spends the same amount per-pupil their district as a whole spends.
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SELECT s."name", e."per_pupil_expenditure", g."graduated"
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FROM "schools" AS s
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JOIN "districts" AS d
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ON s."district_id" = d."id"
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JOIN "expenditures" AS e
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ON d."id" = e."district_id"
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JOIN "graduation_rates" AS g
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ON s."id" = g."school_id"
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ORDER BY e."per_pupil_expenditure" DESC, s."name" ASC;
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33
12.sql
33
12.sql
@@ -0,0 +1,33 @@
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-- write a SQL query to find public school districts with above-average per-pupil expenditures and
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-- an above-average percentage of teachers rated “exemplary”. Your query should return the districts’ names,
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-- along with their per-pupil expenditures and percentage of teachers rated exemplary. Sort the results first by
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-- the percentage of teachers rated exemplary (high to low), then by the per-pupil expenditure (high to low).
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-- You might find it helpful to know that subqueries can be inserted into most any part of a SQL query,
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-- including conditions. For instance, the following is valid SQL syntax:
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-- SELECT "column" FROM "table"
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-- WHERE "column" > (
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-- SELECT AVG("column")
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-- FROM "table"
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-- );
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SELECT
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d."name",
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e."per_pupil_expenditure",
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s."exemplary"
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FROM "districts" AS d
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JOIN "expenditures" AS e
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ON d."id" = e."district_id"
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JOIN "staff_evaluations" AS s
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ON d."id" = s."district_id"
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WHERE d."type" = 'Public School District'
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AND e."per_pupil_expenditure" > (
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SELECT AVG("per_pupil_expenditure")
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FROM "expenditures"
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)
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AND s."exemplary" > (
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SELECT AVG("exemplary")
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FROM "staff_evaluations"
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)
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ORDER BY s."exemplary" DESC, e."per_pupil_expenditure" DESC;
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21
13.sql
21
13.sql
@@ -0,0 +1,21 @@
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-- write a SQL query to answer a question you have about the data! The query should:
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--
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-- Involve at least one JOIN or subquery
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-- Which schools have the highest graduation rates in districts that spend less than the average per-pupil expenditure?
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SELECT
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s."name" AS "school",
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d."name" AS "district",
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e."per_pupil_expenditure",
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g."graduated"
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FROM "schools" AS s
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JOIN "districts" AS d
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ON s."district_id" = d."id"
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JOIN "expenditures" AS e
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ON d."id" = e."district_id"
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JOIN "graduation_rates" AS g
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ON s."id" = g."school_id"
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WHERE e."per_pupil_expenditure" < (
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SELECT AVG("per_pupil_expenditure")
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FROM "expenditures"
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)
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ORDER BY g."graduated" DESC, s."name" ASC;
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