automated commit by check50 [check50=True]

11.sql

@@ -4,7 +4,7 @@
 --
 -- You should assume a school spends the same amount per-pupil their district as a whole spends.
 SELECT s."name", e."per_pupil_expenditure", g."graduated"
-FROM "schools" AS s
+FROM "districts" AS d
 JOIN "districts" AS d
     ON s."district_id" = d."id"
 JOIN "expenditures" AS e

12.sql

@@ -0,0 +1,23 @@
+-- write a SQL query to find public school districts with above-average per-pupil expenditures and
+-- an above-average percentage of teachers rated “exemplary”. Your query should return the districts’ names,
+-- along with their per-pupil expenditures and percentage of teachers rated exemplary. Sort the results first by
+-- the percentage of teachers rated exemplary (high to low), then by the per-pupil expenditure (high to low).
+
+-- You might find it helpful to know that subqueries can be inserted into most any part of a SQL query,
+-- including conditions. For instance, the following is valid SQL syntax:
+
+-- SELECT "column" FROM "table"
+-- WHERE "column" > (
+--     SELECT AVG("column")
+--     FROM "table"
+-- );
+
+SELECT d."name", e."per_pupil_expenditure", g."graduated"
+FROM "schools" AS s
+JOIN "districts" AS d
+    ON s."district_id" = d."id"
+JOIN "expenditures" AS e
+    ON d."id" = e."district_id"
+JOIN "graduation_rates" AS g
+    ON s."id" = g."school_id"
+ORDER BY e."per_pupil_expenditure" DESC, s."name" ASC;