ch20: time x processes graph
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@@ -367,7 +367,7 @@
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{
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"data": {
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"text/plain": [
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"Text(0.5, 0, 'processes')"
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"<matplotlib.lines.Line2D at 0x117430d90>"
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]
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},
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"execution_count": 4,
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@@ -376,7 +376,7 @@
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},
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{
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"data": {
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"image/png": 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"image/png": 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truncated
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"text/plain": [
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"<Figure size 432x288 with 1 Axes>"
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]
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@@ -388,10 +388,11 @@
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}
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],
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"source": [
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"plt.plot('procs', 'median', data=df, marker='+')\n",
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"plt.plot('procs', 'median', data=df, marker='+', linestyle=\"None\")\n",
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"plt.ylim([0, 50])\n",
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"plt.ylabel('time (s)')\n",
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"plt.xlabel('processes')\n"
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"plt.xlabel('processes')\n",
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"plt.axhline(min(median_times), color='red')"
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]
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},
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{
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@@ -402,7 +403,7 @@
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"\n",
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"1. O eixo x são valores discretos: a quantidade de processos em uso. Como faço para que o eixo x seja marcado com os números de 1 a 20, um por um (20 ticks)? \n",
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"2. Como alargar o retângulo do gráfico uns 50%, para que os números no eixo x não fiquem muito apertados?\n",
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"3. Como exibir uma linha horizontal na altura do valor mínimo, que é 10.39?\n"
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"3. ~~Como exibir uma linha horizontal na altura do valor mínimo, que é 10.39?~~ feito: [fonte](https://twitter.com/hcpyz/status/1355310776916062211)\n"
|
||||
]
|
||||
},
|
||||
{
|
||||
|
||||
Reference in new issue
Block a user