Fixed bulleted list

I was using HTML, which doesn't render in the PDF. Switched to
markdown and it is better.
This commit is contained in:
Roger Labbe committed 2018-02-02 10:50:15 -08:00
1 parent d86fb065cb
commit a71401a7b8
1 file changed
+202 -199
+202 -199
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@@ -364,7 +364,7 @@
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9c7fa8710>"
"<matplotlib.figure.Figure at 0x18691f815f8>"
]
},
"metadata": {},
@@ -430,13 +430,11 @@
"\n",
"The details will be different than the univariate filter because these are vectors and matrices, but the concepts are exactly the same: \n",
"\n",
"<ul>\n",
" <li>Use a Gaussian to represent our estimate of the state and error<l/i>\n",
" <li>Use a Gaussian to represent the measurement and its error<l/i>\n",
" <li>Use a Gaussian to represent the process model<l/i>\n",
" <li>Use the process model to predict the next state (the prior)<l/i>\n",
" <li>Form an estimate part way between the measurement and the prior<l/i>\n",
"</ul>\n",
"- Use a Gaussian to represent our estimate of the state and error\n",
"- Use a Gaussian to represent the measurement and its error\n",
"- Use a Gaussian to represent the process model\n",
"- Use the process model to predict the next state (the prior)\n",
"- Form an estimate part way between the measurement and the prior\n",
"\n",
"Your job as a designer will be to design the state $\\left(\\mathbf x, \\mathbf P\\right)$, the process $\\left(\\mathbf F, \\mathbf Q\\right)$, the measurement $\\left(\\mathbf z, \\mathbf R\\right)$, and the measurement function $\\mathbf H$. If the system has control inputs, such as a robot, you will also design $\\mathbf B$ and $\\mathbf u$."
]
@@ -537,8 +535,8 @@
{
"data": {
"text/plain": [
"array([[ 10.0],\n",
" [ 4.5]])"
"array([[ 1000. ],\n",
" [ 4.5]])"
]
},
"execution_count": 4,
@@ -547,7 +545,7 @@
}
],
"source": [
"x = np.array([[10.0],\n",
"x = np.array([[1000.0],\n",
" [4.5]])\n",
"x"
]
@@ -567,8 +565,8 @@
{
"data": {
"text/plain": [
"array([[ 10.0],\n",
" [ 4.5]])"
"array([[ 10. ],\n",
" [ 4.5]])"
]
},
"execution_count": 5,
@@ -596,7 +594,7 @@
{
"data": {
"text/plain": [
"array([ 10.0, 4.5])"
"array([ 10. , 4.5])"
]
},
"execution_count": 6,
@@ -624,7 +622,7 @@
{
"data": {
"text/plain": [
"array([ 1.0, 0.0, 0.0, 0.0, 0.0, 0.0])"
"array([ 1., 0., 0., 0., 0., 0.])"
]
},
"execution_count": 7,
@@ -654,13 +652,13 @@
"name": "stdout",
"output_type": "stream",
"text": [
"[[ 19.0]\n",
" [ 48.0]]\n",
"[[ 19.]\n",
" [ 48.]]\n",
"\n",
"[[ 19.0]\n",
" [ 48.0]]\n",
"[[ 19.]\n",
" [ 48.]]\n",
"\n",
"[ 19.0 48.0]\n"
"[ 19. 48.]\n"
]
}
],
@@ -716,8 +714,8 @@
{
"data": {
"text/plain": [
"array([[ 5e+02, 0.0],\n",
" [ 0.0, 49.0]])"
"array([[ 500., 0.],\n",
" [ 0., 49.]])"
]
},
"execution_count": 9,
@@ -745,8 +743,8 @@
{
"data": {
"text/plain": [
"array([[ 5e+02, 0.0],\n",
" [ 0.0, 49.0]])"
"array([[ 500., 0.],\n",
" [ 0., 49.]])"
]
},
"execution_count": 10,
@@ -779,11 +777,12 @@
"\n",
"$$ x = v \\Delta t + x_0$$\n",
"\n",
"We implemented this as follows, where `pos` and `movement` are Gaussian tuples:\n",
"We implemented this as follows:\n",
"\n",
"```python\n",
"def predict(pos, movement):\n",
" return (pos[0] + movement[0], pos[1] + movement[1])\n",
" return gaussian(pos.mean + movement.mean, \n",
" movement.var + movement.var)\n",
"```\n",
"\n",
"We will do the same thing in this chapter, using multivariate Gaussians instead of univariate Gaussians. You might imagine this sort of implementation:\n",
@@ -822,8 +821,8 @@
{
"data": {
"text/plain": [
"array([[ 1.0],\n",
" [ 2.0]])"
"array([[ 1.],\n",
" [ 2.]])"
]
},
"execution_count": 11,
@@ -847,6 +846,10 @@
"\n",
"$$\\mathbf{\\bar x} = \\mathbf{Fx}$$\n",
"\n",
"which we can make explicit as\n",
"\n",
"$$\\begin{bmatrix} \\bar x \\\\ \\dot{\\bar x}\\end{bmatrix} = \\begin{bmatrix}? & ? \\\\? & ?\\end{bmatrix}\\begin{bmatrix}x\\\\\\dot x\\end{bmatrix}$$\n",
"\n",
"Our job as Kalman filters designers is to specify $\\mathbf F$ such that $\\bar{\\mathbf x} = \\mathbf{Fx}$ performs the innovation (prediction) for our system. To do this we need one equation for each state variable. In our problem $\\mathbf x = \\begin{bmatrix}x & \\dot x\\end{bmatrix}^\\mathtt{T}$, so we need one equation to compute the position $x$ and another to compute the velocity $\\dot x$ . We already know the equation for the position innovation:\n",
"\n",
"$$\\bar x = x + \\dot x \\Delta t$$\n",
@@ -880,7 +883,7 @@
"\\mathbf{\\bar x} &= \\mathbf{Fx}\n",
"\\end{aligned}$$\n",
"\n",
"$\\mathbf F$ is called the *state transition function*."
"$\\mathbf F$ is called the *state transition function* or the *state transition matrix*. In later chapters it will be a true function, not a matrix, so calling it a function is a bit more general."
]
},
{
@@ -891,8 +894,8 @@
{
"data": {
"text/plain": [
"array([[ 1.0, 0.1],\n",
" [ 0.0, 1.0]])"
"array([[ 1. , 0.1],\n",
" [ 0. , 1. ]])"
]
},
"execution_count": 12,
@@ -923,7 +926,7 @@
"name": "stdout",
"output_type": "stream",
"text": [
"x = [ 10.4 4.5]\n"
"x = [ 10.45 4.5 ]\n"
]
}
],
@@ -957,10 +960,10 @@
"name": "stdout",
"output_type": "stream",
"text": [
"x = [ 10.9 4.5]\n",
"x = [ 11.3 4.5]\n",
"x = [ 11.8 4.5]\n",
"x = [ 12.2 4.5]\n"
"x = [ 10.9 4.5]\n",
"x = [ 11.35 4.5 ]\n",
"x = [ 11.8 4.5]\n",
"x = [ 12.25 4.5 ]\n"
]
}
],
@@ -986,8 +989,8 @@
"name": "stdout",
"output_type": "stream",
"text": [
"[[ 5.12e+02 24.5]\n",
" [ 24.5 49.0]]\n"
"[[ 512.25 24.5 ]\n",
" [ 24.5 49. ]]\n"
]
}
],
@@ -1015,7 +1018,7 @@
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9ca12b358>"
"<matplotlib.figure.Figure at 0x186940eb390>"
]
},
"metadata": {},
@@ -1075,8 +1078,8 @@
"name": "stdout",
"output_type": "stream",
"text": [
"[[ 0.588 1.18]\n",
" [ 1.18 2.35]]\n"
"[[ 0.588 1.175]\n",
" [ 1.175 2.35 ]]\n"
]
}
],
@@ -1118,9 +1121,9 @@
"name": "stdout",
"output_type": "stream",
"text": [
"x = [ 12.7 4.5]\n",
"P = [[ 6.81e+02 3.01e+02]\n",
" [ 3.01e+02 5.02e+02]]\n"
"x = [ 12.7 4.5]\n",
"P = [[ 680.587 301.175]\n",
" [ 301.175 502.35 ]]\n"
]
}
],
@@ -1346,7 +1349,7 @@
"name": "stdout",
"output_type": "stream",
"text": [
"x = [ 1.09 -0.64]\n"
"x = [ 1.085 -0.64 ]\n"
]
}
],
@@ -1389,11 +1392,11 @@
"name": "stdout",
"output_type": "stream",
"text": [
"x = [[ 0.0 0.0]]\n",
"R = [[ 1.0]]\n",
"x = [[ 0. 0.]]\n",
"R = [[ 1.]]\n",
"Q = \n",
" [[ 1.0 0.0]\n",
" [ 0.0 1.0]]\n"
" [[ 1. 0.]\n",
" [ 0. 1.]]\n"
]
}
],
@@ -1556,9 +1559,9 @@
"outputs": [
{
"data": {
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truncated
"image/png": 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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9ca194b70>"
"<matplotlib.figure.Figure at 0x18693befb00>"
]
},
"metadata": {},
@@ -1568,7 +1571,7 @@
"data": {
"image/png": 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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9cb2026d8>"
"<matplotlib.figure.Figure at 0x186951a06a0>"
]
},
"metadata": {},
@@ -1608,7 +1611,7 @@
"data": {
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truncated
"text/plain": [
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@@ -1760,7 +1763,7 @@
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9cbe4f5c0>"
"<matplotlib.figure.Figure at 0x18694144160>"
]
},
"metadata": {},
@@ -1805,7 +1808,7 @@
{
"data": {
"application/vnd.jupyter.widget-view+json": {
"model_id": "e1ad782948d04785983c0c5b1e922df9",
"model_id": "c377c5e3efb74ffa94016da4d50d9f2d",
"version_major": 2,
"version_minor": 0
},
@@ -1998,7 +2001,7 @@
"data": {
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9cb2091d0>"
"<matplotlib.figure.Figure at 0x1869518cbe0>"
]
},
"metadata": {},
@@ -2130,7 +2133,7 @@
"data": {
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9cb229f28>"
"<matplotlib.figure.Figure at 0x1869518c630>"
]
},
"metadata": {},
@@ -2219,7 +2222,7 @@
"data": {
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9cb3629e8>"
"<matplotlib.figure.Figure at 0x18695288ef0>"
]
},
"metadata": {},
@@ -2246,7 +2249,7 @@
"data": {
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9cb637940>"
"<matplotlib.figure.Figure at 0x1869530d470>"
]
},
"metadata": {},
@@ -2348,7 +2351,7 @@
"data": {
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9cb600128>"
"<matplotlib.figure.Figure at 0x186955ca6d8>"
]
},
"metadata": {},
@@ -2358,7 +2361,7 @@
"data": {
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9cba3b898>"
"<matplotlib.figure.Figure at 0x18695e0c320>"
]
},
"metadata": {},
@@ -2402,7 +2405,7 @@
"data": {
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9cb1f9828>"
"<matplotlib.figure.Figure at 0x186955c2320>"
]
},
"metadata": {},
@@ -2430,7 +2433,7 @@
"data": {
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9cb237668>"
"<matplotlib.figure.Figure at 0x186938c0a20>"
]
},
"metadata": {},
@@ -2459,7 +2462,7 @@
"data": {
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9cb202a20>"
"<matplotlib.figure.Figure at 0x18695219cf8>"
]
},
"metadata": {},
@@ -2499,7 +2502,7 @@
"data": {
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9cb27f748>"
"<matplotlib.figure.Figure at 0x186952e2f28>"
]
},
"metadata": {},
@@ -2509,7 +2512,7 @@
"data": {
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9cb38f080>"
"<matplotlib.figure.Figure at 0x186952f4b00>"
]
},
"metadata": {},
@@ -2552,7 +2555,7 @@
"data": {
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9cbbb7320>"
"<matplotlib.figure.Figure at 0x186960693c8>"
]
},
"metadata": {},
@@ -2562,7 +2565,7 @@
"data": {
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9cb9b5358>"
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]
},
"metadata": {},
@@ -2594,7 +2597,7 @@
"data": {
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9ca138c18>"
"<matplotlib.figure.Figure at 0x18693957828>"
]
},
"metadata": {},
@@ -2625,7 +2628,7 @@
"data": {
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9cb1e3ac8>"
"<matplotlib.figure.Figure at 0x1869517f860>"
]
},
"metadata": {},
@@ -2658,7 +2661,7 @@
"data": {
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9cb30e198>"
"<matplotlib.figure.Figure at 0x186951e2550>"
]
},
"metadata": {},
@@ -2739,7 +2742,7 @@
"data": {
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9cb63fcf8>"
"<matplotlib.figure.Figure at 0x1869593bba8>"
]
},
"metadata": {},
@@ -2793,7 +2796,7 @@
"output_type": "stream",
"text": [
"[[ 3.2]\n",
" [ 0.0]]\n"
" [ 0. ]]\n"
]
}
],
@@ -2861,7 +2864,7 @@
"data": {
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9cbbc2ba8>"
"<matplotlib.figure.Figure at 0x1869579c048>"
]
},
"metadata": {},
@@ -2904,7 +2907,7 @@
"data": {
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9cbbc26a0>"
"<matplotlib.figure.Figure at 0x18695981f60>"
]
},
"metadata": {},
@@ -2944,7 +2947,7 @@
"data": {
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truncated
"text/plain": [
"<matplotlib.figure.Figure at 0x2b9ca15edd8>"
"<matplotlib.figure.Figure at 0x18695dfa358>"
]
},
"metadata": {},
@@ -3001,7 +3004,7 @@
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truncated
"text/plain": "<matplotlib.figure.Figure at 0x2298ad62c18>"
"text/plain": "<matplotlib.figure.Figure at 0x18694177940>"
},
"metadata": {},
"output_type": "display_data"
@@ -3247,36 +3269,17 @@
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