some typos

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Fang Liu committed 2025-08-29 13:52:29 +08:00
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@@ -380,7 +380,7 @@ this by the inverse property. Whereas, by expressing $a=b^{\log_b(a)}$ we have:
$$
a^{(\log_b(x)/\log_b(b))} = (b^{\log_b(a)})^{(\log_b(x)/\log_b(a))} =
a^{(\log_b(x)/\log_b(a))} = (b^{\log_b(a)})^{(\log_b(x)/\log_b(a))} =
b^{\log_b(a) \cdot \log_b(x)/\log_b(a) } = b^{\log_b(x)} = x.
$$