some typos

quarto/limits/limits.qmd

@@ -311,7 +311,7 @@ This progression can be seen to be increasing. Cauchy, in his treatise, can see
 
 $$
 \begin{align*}
-(1 + \frac{1}{m})^n &= 1 + \frac{1}{1} + \frac{1}{1\cdot 2}(1 - \frac{1}{m}) +  \\
+(1 + \frac{1}{m})^m &= 1 + \frac{1}{1} + \frac{1}{1\cdot 2}(1 - \frac{1}{m}) +  \\
 & \frac{1}{1\cdot 2\cdot 3}(1 - \frac{1}{m})(1 -  \frac{2}{m}) + \cdots \\
 &+
 \frac{1}{1 \cdot 2 \cdot \cdots \cdot m}(1 - \frac{1}{m}) \cdot \cdots \cdot (1 - \frac{m-1}{m}).

quarto/precalc/exp_log_functions.qmd

@@ -380,7 +380,7 @@ this by the inverse property. Whereas, by expressing $a=b^{\log_b(a)}$ we have:
 
 
 $$
-a^{(\log_b(x)/\log_b(b))} = (b^{\log_b(a)})^{(\log_b(x)/\log_b(a))} =
+a^{(\log_b(x)/\log_b(a))} = (b^{\log_b(a)})^{(\log_b(x)/\log_b(a))} =
 b^{\log_b(a) \cdot \log_b(x)/\log_b(a) } = b^{\log_b(x)} = x.
 $$