Solution to problem 17 part 2 in Python

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David Doblas Jiménez 2022-01-07 16:16:55 +01:00
parent 606c111e32
commit 93ea53841c

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@ -217,5 +217,311 @@ def part_1() -> None:
print(f"After 6 cycles in 3D, we have {len(active_points)} active cubes")
# --- Part Two ---
# For some reason, your simulated results don't match what the experimental
# energy source engineers expected. Apparently, the pocket dimension actually
# has four spatial dimensions, not three.
# The pocket dimension contains an infinite 4-dimensional grid. At every
# integer 4-dimensional coordinate (x,y,z,w), there exists a single cube
# (really, a hypercube) which is still either active or inactive.
# Each cube only ever considers its neighbors: any of the 80 other cubes where
# any of their coordinates differ by at most 1. For example, given the cube at
# x=1,y=2,z=3,w=4, its neighbors include the cube at x=2,y=2,z=3,w=3, the cube
# at x=0,y=2,z=3,w=4, and so on.
# The initial state of the pocket dimension still consists of a small flat
# region of cubes. Furthermore, the same rules for cycle updating still apply:
# during each cycle, consider the number of active neighbors of each cube.
# For example, consider the same initial state as in the example above. Even
# though the pocket dimension is 4-dimensional, this initial state represents a
# small 2-dimensional slice of it. (In particular, this initial state defines a
# 3x3x1x1 region of the 4-dimensional space.)
# Simulating a few cycles from this initial state produces the following
# configurations, where the result of each cycle is shown layer-by-layer at
# each given z and w coordinate:
# Before any cycles:
# z=0, w=0
# .#.
# ..#
# ###
# After 1 cycle:
# z=-1, w=-1
# #..
# ..#
# .#.
# z=0, w=-1
# #..
# ..#
# .#.
# z=1, w=-1
# #..
# ..#
# .#.
# z=-1, w=0
# #..
# ..#
# .#.
# z=0, w=0
# #.#
# .##
# .#.
# z=1, w=0
# #..
# ..#
# .#.
# z=-1, w=1
# #..
# ..#
# .#.
# z=0, w=1
# #..
# ..#
# .#.
# z=1, w=1
# #..
# ..#
# .#.
# After 2 cycles:
# z=-2, w=-2
# .....
# .....
# ..#..
# .....
# .....
# z=-1, w=-2
# .....
# .....
# .....
# .....
# .....
# z=0, w=-2
# ###..
# ##.##
# #...#
# .#..#
# .###.
# z=1, w=-2
# .....
# .....
# .....
# .....
# .....
# z=2, w=-2
# .....
# .....
# ..#..
# .....
# .....
# z=-2, w=-1
# .....
# .....
# .....
# .....
# .....
# z=-1, w=-1
# .....
# .....
# .....
# .....
# .....
# z=0, w=-1
# .....
# .....
# .....
# .....
# .....
# z=1, w=-1
# .....
# .....
# .....
# .....
# .....
# z=2, w=-1
# .....
# .....
# .....
# .....
# .....
# z=-2, w=0
# ###..
# ##.##
# #...#
# .#..#
# .###.
# z=-1, w=0
# .....
# .....
# .....
# .....
# .....
# z=0, w=0
# .....
# .....
# .....
# .....
# .....
# z=1, w=0
# .....
# .....
# .....
# .....
# .....
# z=2, w=0
# ###..
# ##.##
# #...#
# .#..#
# .###.
# z=-2, w=1
# .....
# .....
# .....
# .....
# .....
# z=-1, w=1
# .....
# .....
# .....
# .....
# .....
# z=0, w=1
# .....
# .....
# .....
# .....
# .....
# z=1, w=1
# .....
# .....
# .....
# .....
# .....
# z=2, w=1
# .....
# .....
# .....
# .....
# .....
# z=-2, w=2
# .....
# .....
# ..#..
# .....
# .....
# z=-1, w=2
# .....
# .....
# .....
# .....
# .....
# z=0, w=2
# ###..
# ##.##
# #...#
# .#..#
# .###.
# z=1, w=2
# .....
# .....
# .....
# .....
# .....
# z=2, w=2
# .....
# .....
# ..#..
# .....
# .....
# After the full six-cycle boot process completes, 848 cubes are left in the
# active state.
# Starting with your given initial configuration, simulate six cycles in a
# 4-dimensional space. How many cubes are left in the active state after the
# sixth cycle?
def part_2() -> None:
active_points = get_active_points(dim=4)
for it in range(6):
new_active_points = set()
# check x,y,z point
for x in range(-10 - it, it + 10):
for y in range(-10 - it, it + 10):
for z in range(-2 - it, it + 2):
for w in range(-2 - it, it + 2):
point = (x, y, z, w)
# for the current point, check the neighbors
num_actives = 0
for delta in iter.product(range(-1, 2), repeat=4):
if delta != (0,) * 4:
if (
tuple(
[a + b for a, b in zip(point, delta)]
)
in active_points
):
num_actives += 1
# apply rules
if point in active_points and (
num_actives == 2 or num_actives == 3
):
new_active_points.add(point)
if point not in active_points and num_actives == 3:
new_active_points.add(point)
# next iteration
active_points = new_active_points
print(f"After 6 cycles in 4D, we have {len(active_points)} active cubes")
if __name__ == "__main__":
part_1()
part_2()