Add subdirectories
Add /ipynb/ and /py/ subdirectories to keep the home page neater.
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py/sudoku.py
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161
py/sudoku.py
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## Solve Every Sudoku Puzzle
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## See http://norvig.com/sudoku.html
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## Throughout this program we have:
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## r is a row, e.g. 'A'
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## c is a column, e.g. '3'
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## s is a square, e.g. 'A3'
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## d is a digit, e.g. '9'
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## u is a unit, e.g. ['A1','B1','C1','D1','E1','F1','G1','H1','I1']
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## grid is a grid,e.g. 81 non-blank chars, e.g. starting with '.18...7...
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## values is a dict of possible values, e.g. {'A1':'12349', 'A2':'8', ...}
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def cross(A, B):
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"Cross product of elements in A and elements in B."
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return [a+b for a in A for b in B]
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digits = '123456789'
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rows = 'ABCDEFGHI'
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cols = digits
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squares = cross(rows, cols)
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unitlist = ([cross(rows, c) for c in cols] +
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[cross(r, cols) for r in rows] +
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[cross(rs, cs) for rs in ('ABC','DEF','GHI') for cs in ('123','456','789')])
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units = dict((s, [u for u in unitlist if s in u])
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for s in squares)
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peers = dict((s, set(sum(units[s],[]))-set([s]))
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for s in squares)
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################ Unit Tests ################
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def test():
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"A set of tests that must pass."
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assert len(squares) == 81
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assert len(unitlist) == 27
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assert all(len(units[s]) == 3 for s in squares)
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assert all(len(peers[s]) == 20 for s in squares)
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assert units['C2'] == [['A2', 'B2', 'C2', 'D2', 'E2', 'F2', 'G2', 'H2', 'I2'],
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['C1', 'C2', 'C3', 'C4', 'C5', 'C6', 'C7', 'C8', 'C9'],
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['A1', 'A2', 'A3', 'B1', 'B2', 'B3', 'C1', 'C2', 'C3']]
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assert peers['C2'] == set(['A2', 'B2', 'D2', 'E2', 'F2', 'G2', 'H2', 'I2',
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'C1', 'C3', 'C4', 'C5', 'C6', 'C7', 'C8', 'C9',
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'A1', 'A3', 'B1', 'B3'])
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print('All tests pass.')
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################ Parse a Grid ################
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def parse_grid(grid):
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"""Convert grid to a dict of possible values, {square: digits}, or
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return False if a contradiction is detected."""
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## To start, every square can be any digit; then assign values from the grid.
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values = dict((s, digits) for s in squares)
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for s,d in grid_values(grid).items():
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if d in digits and not assign(values, s, d):
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return False ## (Fail if we can't assign d to square s.)
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return values
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def grid_values(grid):
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"Convert grid into a dict of {square: char} with '0' or '.' for empties."
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chars = [c for c in grid if c in digits or c in '0.']
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if len(chars) != 81: print(grid, chars, len(chars))
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assert len(chars) == 81
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return dict(zip(squares, chars))
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################ Constraint Propagation ################
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def assign(values, s, d):
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"""Eliminate all the other values (except d) from values[s] and propagate.
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Return values, except return False if a contradiction is detected."""
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other_values = values[s].replace(d, '')
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if all(eliminate(values, s, d2) for d2 in other_values):
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return values
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else:
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return False
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def eliminate(values, s, d):
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"""Eliminate d from values[s]; propagate when values or places <= 2.
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Return values, except return False if a contradiction is detected."""
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if d not in values[s]:
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return values ## Already eliminated
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values[s] = values[s].replace(d,'')
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## (1) If a square s is reduced to one value d2, then eliminate d2 from the peers.
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if len(values[s]) == 0:
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return False ## Contradiction: removed last value
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elif len(values[s]) == 1:
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d2 = values[s]
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if not all(eliminate(values, s2, d2) for s2 in peers[s]):
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return False
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## (2) If a unit u is reduced to only one place for a value d, then put it there.
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for u in units[s]:
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dplaces = [s for s in u if d in values[s]]
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if len(dplaces) == 0:
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return False ## Contradiction: no place for this value
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elif len(dplaces) == 1:
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# d can only be in one place in unit; assign it there
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if not assign(values, dplaces[0], d):
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return False
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return values
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################ Display as 2-D grid ################
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def display(values):
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"Display these values as a 2-D grid."
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width = 1+max(len(values[s]) for s in squares)
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line = '+'.join(['-'*(width*3)]*3)
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for r in rows:
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print(''.join(values[r+c].center(width) + ('|' if c in '36' else '')
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for c in cols))
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if r in 'CF': print(line)
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print()
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################ Search ################
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def solve(grid): return search(parse_grid(grid))
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def search(values):
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"Using depth-first search and propagation, try all possible values."
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if values is False:
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return False ## Failed earlier
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if all(len(values[s]) == 1 for s in squares):
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return values ## Solved!
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## Chose the unfilled square s with the fewest possibilities
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n,s = min((len(values[s]), s) for s in squares if len(values[s]) > 1)
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for d in values[s]:
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result = search(assign(values.copy(), s, d))
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if result: return result
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################ System test ################
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import time
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def solve_all(grids, name=''):
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"""Attempt to solve a sequence of grids. Report results."""
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times, results = zip(*[time_solve(grid) for grid in grids])
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N = len(results)
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if N > 1:
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print("Solved %d of %d %s puzzles (avg %.2f secs (%d Hz), max %.2f secs)." % (
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sum(results), N, name, sum(times)/N, N/sum(times), max(times)))
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def time_solve(grid):
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start = time.clock()
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values = solve(grid)
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t = time.clock()-start
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return (t, solved(values))
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def solved(values):
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"A puzzle is solved if each unit is a permutation of the digits 1 to 9."
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def unitsolved(unit): return set(values[s] for s in unit) == set(digits)
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return values is not False and all(unitsolved(unit) for unit in unitlist)
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grid1 = '003020600900305001001806400008102900700000008006708200002609500800203009005010300'
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grid2 = '4.....8.5.3..........7......2.....6.....8.4......1.......6.3.7.5..2.....1.4......'
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hard1 = '.....6....59.....82....8....45........3........6..3.54...325..6..................'
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if __name__ == '__main__':
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test()
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solve_all(open("sudoku-easy50.txt"), "easy")
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solve_all(open("sudoku-top95.txt"), "hard")
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solve_all(open("sudoku-hardest.txt"), "hardest")
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