40 lines
994 B
Python
40 lines
994 B
Python
#!/usr/bin/env python
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"""
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Created on 17 Jun 2017
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@author: David Doblas Jiménez
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@email: daviddoji@pm.me
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Solution for problem 6 of Project Euler
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https://projecteuler.net/problem=6
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"""
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from utils import timeit
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@timeit("Problem 6")
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def compute():
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"""
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The sum of the squares of the first ten natural numbers is,
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1^2 + 2^2 + ... + 10^2 = 385
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The square of the sum of the first ten natural numbers is,
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(1 + 2 + ... + 10)^2 = 55^2 = 3025
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Hence the difference between the sum of the squares of the first ten
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natural numbers and the square of the sum is 3025 − 385 = 2640.
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Find the difference between the sum of the squares of the first one
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hundred natural numbers and the square of the sum.
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"""
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n = 100
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square_of_sum = sum(i for i in range(1, n + 1)) ** 2
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sum_squares = sum(i**2 for i in range(1, n + 1))
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diff = square_of_sum - sum_squares
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return diff
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if __name__ == "__main__":
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print(f"Result for Problem 6 is {compute()}")
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