#= Created on 01 Sep 2021 @author: David Doblas Jiménez @email: daviddoji@pm.me Solution for Problem 33 of Project Euler https://projecteuler.net/problem=33 =# using BenchmarkTools function Problem33() #= The fraction 49/98 is a curious fraction, as an inexperienced mathematician in attempting to simplify it may incorrectly believe that 49/98 = 4/8, which is correct, is obtained by cancelling the 9s. We shall consider fractions like, 30/50 = 3/5, to be trivial examples. There are exactly four non-trivial examples of this type of fraction, less than one in value, and containing two digits in the numerator and denominator. If the product of these four fractions is given in its lowest common terms, find the value of the denominator. =# numerator = 1 denominator = 1 for x in 10:99 for y in 10:99 if x < y if reverse(digits(x))[2] == reverse(digits(y))[1] if reverse(digits(y))[2] != 0 if reverse(digits(x))[1] / reverse(digits(y))[2] == x / y numerator *= x denominator *= y end end end end end end return Int(denominator/numerator) end println("Time to evaluate Problem 33:") @btime Problem33() println("") println("Result for Problem 33: ", Problem33())