#!/usr/bin/env python3
"""
Created on 12 Sep 2021

@author: David Doblas Jiménez
@email: daviddoji@pm.me

Solution for problem 48 of Project Euler
https://projecteuler.net/problem=48
"""

from utils import timeit


@timeit("Problem 48")
def compute():
    """
    The series, 1^1 + 2^2 + 3^3 + ... + 10^10 = 10405071317.

    Find the last ten digits of the series, 1^1 + 2^2 + 3^3 + ... + 1000^1000.
    """
    series = sum(i**i for i in range(1,1001))
    return str(series)[-10:]


if __name__ == "__main__":

    print(f"Result for Problem 48: {compute()}")