Solution for problems 1,2

src/Python/Problem001.py

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+#!/usr/bin/python3
+"""
+Created on 14 Mar 2017
+
+@author: David Doblas Jiménez
+@email: daviddoji@pm.me
+
+Solution for problem 1 of Project Euler
+https://projecteuler.net/problem=1
+"""
+
+from utils import timeit
+
+
+@timeit("Problem 1")
+def compute():
+    """
+    If we list all the natural numbers below 10 that are multiples of 3 or 5,
+    we get 3, 5, 6 and 9. The sum of these multiples is 23.
+
+    Find the sum of all the multiples of 3 or 5 below 1000.
+    """
+
+    ans = sum(x for x in range(1000) if (x % 3 == 0 or x % 5 == 0))
+    return ans
+
+
+if __name__ == "__main__":
+
+    print(f"Result for problem 1: {compute()}")

src/Python/Problem002.py

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+#!/usr/bin/env python3
+"""
+Created on 14 Mar 2017
+
+@author: David Doblas Jiménez
+@email: daviddoji@pm.me
+
+Solution for problem 2 of Project Euler
+https://projecteuler.net/problem=2
+"""
+
+from utils import timeit
+
+
+@timeit("Problem 2")
+def compute():
+    """
+    Each new term in the Fibonacci sequence is generated by adding the
+    previous two terms. By starting with 1 and 2, the first 10 terms will be:
+
+    1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ...
+
+    Find the sum of all the even-valued terms in the sequence which do not
+    exceed four million.
+    """
+    ans = 0
+    limit = 4_000_000
+    x, y = 1, 1
+    z = x + y  # Because every third Fibonacci number is even
+
+    while z <= limit:
+        ans += z
+        x = y + z
+        y = z + x
+        z = x + y
+    return ans
+
+
+if __name__ == "__main__":
+
+    print(f"Result for problem 2: {compute()}")