diff --git a/src/Julia/Problem043.jl b/src/Julia/Problem043.jl
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+#=
+Created on 13 Sep 2021
+
+@author: David Doblas Jiménez
+@email: daviddoji@pm.me
+
+Solution for Problem 43 of Project Euler
+https://projecteuler.net/problem=43
+=#
+
+using BenchmarkTools
+using Combinatorics
+
+function Problem43()
+    #=
+    The number, 1406357289, is a 0 to 9 pandigital number because
+    it is made up of each of the digits 0 to 9 in some order, but
+    it also has a rather interesting sub-string divisibility property.
+
+    Let d1 be the 1st digit, d2 be the 2nd digit, and so on. In this
+    way, we note the following:
+
+        d2d3d4=406 is divisible by 2
+        d3d4d5=063 is divisible by 3
+        d4d5d6=635 is divisible by 5
+        d5d6d7=357 is divisible by 7
+        d6d7d8=572 is divisible by 11
+        d7d8d9=728 is divisible by 13
+        d8d9d10=289 is divisible by 17
+
+    Find the sum of all 0 to 9 pandigital numbers with this property.
+    =#
+    ans = []
+    pandigital = join(['0', '1', '2', '3', '4', '5', '6', '7', '8', '9'])
+
+    for n in permutations(pandigital)
+        n_ =join(n)
+        if n_[1] != 0 && join(sort(n)) == pandigital
+            if parse(Int, n_[8:end]) % 17 == 0
+                if parse(Int, n_[7:9]) % 13 == 0
+                    if parse(Int, n_[6:8]) % 11 == 0
+                        if parse(Int, n_[5:7]) % 7 == 0
+                            if parse(Int, n_[4:6]) % 5 == 0
+                                if parse(Int, n_[3:5]) % 3 == 0
+                                    if parse(Int, n_[2:4]) % 2 == 0
+                                        push!(ans, n_)
+                                    end
+                                end
+                            end
+                        end
+                    end
+                end
+            end
+        end
+    end
+
+    return sum(parse(Int, num) for num in ans)
+end
+
+
+println("Time to evaluate Problem 43:")
+@btime Problem43()
+println("")
+println("Result for Problem 43: ", Problem43())