Solution to problem 32

src/Python/Problem032.py

@@ -0,0 +1,45 @@
+#!/usr/bin/env python3
+"""
+Created on 26 Feb 2021
+
+@author: David Doblas Jiménez
+@email: daviddoji@pm.me
+
+Solution for problem 32 of Project Euler
+https://projecteuler.net/problem=32
+"""
+
+from utils import timeit
+
+
+@timeit("Problem 32")
+def compute():
+    """
+    We shall say that an n-digit number is pandigital if it makes use of all
+    the digits 1 to n exactly once; for example, the 5-digit number, 15234, is
+    1 through 5 pandigital.
+
+    The product 7254 is unusual, as the identity, 39 × 186 = 7254, containing
+    multiplicand, multiplier, and product is 1 through 9 pandigital.
+
+    Find the sum of all products whose multiplicand/multiplier/product identity
+    can be written as a 1 through 9 pandigital.
+    HINT: Some products can be obtained in more than one way so be sure to only
+    include it once in your sum.
+    """
+
+    ans = set()
+    pandigital = ['1', '2', '3', '4', '5', '6', '7', '8', '9']
+
+    for x in range(1, 100):
+        for y in range(100, 10000):
+            # product = x * y
+            if sorted(str(x) + str(y) + str(x * y)) == pandigital:
+                ans.add(x * y)
+
+    return sum(ans)
+
+
+if __name__ == "__main__":
+
+    print(f"Result for Problem 32: {compute()}")