Solution to problem 50 in Julia

src/Julia/Problem050.jl

@@ -0,0 +1,54 @@
+#=
+Created on 20 Sep 2021
+
+@author: David Doblas Jiménez
+@email: daviddoji@pm.me
+
+Solution for Problem 50 of Project Euler
+https://projecteuler.net/problem=50
+=#
+
+using BenchmarkTools
+using Primes
+
+function Problem50()
+    #=
+    The prime 41, can be written as the sum of six consecutive primes:
+
+        41 = 2 + 3 + 5 + 7 + 11 + 13
+
+    This is the longest sum of consecutive primes that adds to a prime below one-hundred.
+
+    The longest sum of consecutive primes below one-thousand that adds to a prime, 
+    contains 21 terms, and is equal to 953.
+
+    Which prime, below one-million, can be written as the sum of the most consecutive primes?
+    =#
+
+    ans = 0
+    result = 0
+    prime_list = primes(1_000_000)
+
+    for i in 1:length(prime_list)
+        sum = 0
+        count = 0
+        for j in prime_list[i:end]
+            sum += j
+            count += 1
+            if isprime(sum) && count > result
+                result = count
+                ans = sum
+            end
+            if sum > 1_000_000
+                break
+            end
+        end
+    end
+    return ans
+end
+
+
+println("Time to evaluate Problem 50:")
+@btime Problem50()
+println("")
+println("Result for Problem 50: ", Problem50())