Solution to problem 52 in Julia

src/Julia/Problem052.jl

@@ -0,0 +1,33 @@
+#=
+Created on 26 Sep 2021
+
+@author: David Doblas Jiménez
+@email: daviddoji@pm.me
+
+Solution for Problem 52 of Project Euler
+https://projecteuler.net/problem=52
+=#
+
+using BenchmarkTools
+
+function Problem52()
+    #=
+    It can be seen that the number, 125874, and its double, 251748,
+    contain exactly the same digits, but in a different order.
+
+    Find the smallest positive integer, x, such that 2x, 3x, 4x, 5x,
+    and 6x, contain the same digits.
+    =#
+
+    for number in 123456:1_000_000
+        if sort(digits(number)) == sort(digits(2*number)) == sort(digits(3*number)) == sort(digits(4*number)) == sort(digits(5*number)) == sort(digits(6*number))
+            return number
+        end
+    end
+end
+
+
+println("Time to evaluate Problem 52:")
+@btime Problem52()
+println("")
+println("Result for Problem 52: ", Problem52())