Add newline for consistency

src/Julia/Problems001-050/Problem001.jl

@@ -17,6 +17,7 @@ function Problem1()
 
     Find the sum of all the multiples of 3 or 5 below 1000.
     =#
+    
     ans = sum(x for x in 0:999 if x%3==0 || x%5==0)
     
     return ans

src/Julia/Problems001-050/Problem002.jl

@@ -1,23 +1,23 @@
-#=
+#= 
 Created on 08 Jun 2021
 
 @author: David Doblas Jiménez
 @email: daviddoji@pm.me
 
 Solution for Problem 2 of Project Euler
-https://projecteuler.net/problem=2
-=#
+https://projecteuler.net/problem=2 =#
+
+using BenchmarkTools
 
 function Problem2()
-    #=
+    #= 
     Each new term in the Fibonacci sequence is generated by adding the
     previous two terms. By starting with 1 and 2, the first 10 terms will be:
 
     1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ...
 
     Find the sum of all the even-valued terms in the sequence which do not
-    exceed four million.
-    =#
+    exceed four million. =#
 
     ans = 0
     limit = 4_000_000
@@ -35,6 +35,6 @@ end
 
 
 println("Time to evaluate Problem 2:")
-@time Problem2()
+@btime Problem2()
 println("")
 println("Result for Problem 2: ", Problem2())