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David Doblas Jiménez
2021-09-20 18:08:16 +02:00
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#=
Created on 21 Jul 2021
@author: David Doblas Jiménez
@email: daviddoji@pm.me
Solution for Problem 12 of Project Euler
https://projecteuler.net/problem=12
=#
function Problem12()
#=
The sequence of triangle numbers is generated by adding the natural
numbers. So the 7th triangle number would be:
1 + 2 + 3 + 4 + 5 + 6 + 7 = 28.
The first ten terms would be:
1, 3, 6, 10, 15, 21, 28, 36, 45, 55, ...
Let us list the factors of the first seven triangle numbers:
1: 1
3: 1,3
6: 1,2,3,6
10: 1,2,5,10
15: 1,3,5,15
21: 1,3,7,21
28: 1,2,4,7,14,28
We can see that 28 is the first triangle number to have over five divisors.
What is the value of the first triangle number to have over five hundred
divisors?
=#
function num_divisors(n)
r = isqrt(n)
2 * count(n % i == 0 for i in 1:r) - (r^2 == n)
end
triangle = 0
for i in Iterators.countfrom(1)
triangle += i
if num_divisors(triangle) > 500
return string(triangle)
end
end
end
println("Time to evaluate Problem 12:")
@time Problem12()
println("")
println("Result for Problem 12: ", Problem12())