Adopted new convention from template

src/Python/Problems001-050/Problem038.py

@@ -1,4 +1,4 @@
-#!/usr/bin/env python3
+#!/usr/bin/env python
 """
 Created on 03 Jun 2021
 
@@ -17,25 +17,24 @@ def compute():
     """
     Take the number 192 and multiply it by each of 1, 2, and 3:
 
-      192 × 1 = 192
+      192 x 1 = 192
-      192 × 2 = 384
+      192 x 2 = 384
-      192 × 3 = 576
+      192 x 3 = 576
 
-    By concatenating each product we get the 1 to 9 pandigital, 
+    By concatenating each product we get the 1 to 9 pandigital,
-    192384576. We will call 192384576 the concatenated product of 
+    192384576. We will call 192384576 the concatenated product of
     192 and (1,2,3)
 
-    The same can be achieved by starting with 9 and multiplying by 
+    The same can be achieved by starting with 9 and multiplying by
-    1, 2, 3, 4, and 5, giving the pandigital, 918273645, which is 
+    1, 2, 3, 4, and 5, giving the pandigital, 918273645, which is
     the concatenated product of 9 and (1,2,3,4,5).
 
     What is the largest 1 to 9 pandigital 9-digit number that can
-    be formed as the concatenated product of an integer with 
+    be formed as the concatenated product of an integer with
     (1,2, ... , n) where n > 1?
-
     """
 
-    results = []
+    ans = []
     # Number must 4 digits (exactly) to be pandigital
     # if n > 1
     for i in range(1, 10_000):
@@ -43,14 +42,13 @@ def compute():
         number = ""
         while len(number) < 9:
             number += str(integer * i)
-            if sorted(number) == list('123456789'):
+            if sorted(number) == list("123456789"):
-                results.append(number)
+                ans.append(number)
-    
+
             integer += 1
-    
+
-    return max(results)
+    return max(ans)
 
 
 if __name__ == "__main__":
-
+    print(f"Result for Problem 38 is {compute()}")
-    print(f"Result for Problem 38: {compute()}")