Solution to problem 42 in Julia

src/Julia/Problem042.jl

@@ -0,0 +1,55 @@
+#=
+Created on 12 Sep 2021
+
+@author: David Doblas Jiménez
+@email: daviddoji@pm.me
+
+Solution for Problem 42 of Project Euler
+https://projecteuler.net/problem=42
+=#
+
+using BenchmarkTools
+using DelimitedFiles
+
+function triangle_number(num)
+    return Int(0.5*num*(num+1))
+end
+
+function word_to_value(word)
+    return sum(Int(letter)-64 for letter in word)
+end
+
+function Problem42()
+    #=
+    The nth term of the sequence of triangle numbers is given by, tn = ½n(n+1);
+    so the first ten triangle numbers are:
+
+        1, 3, 6, 10, 15, 21, 28, 36, 45, 55, ...
+
+    By converting each letter in a word to a number corresponding to its alphabetical
+    position and adding these values we form a word value. For example, the word value
+    for SKY is 19 + 11 + 25 = 55 = t10. If the word value is a triangle number then we
+    shall call the word a triangle word.
+
+    Using words.txt, a 16K text file containing nearly two-thousand common English words,
+    how many are triangle words?
+    =#
+
+    triangular_numbers = [triangle_number(n) for n in 1:26]
+    ans = 0
+    file = "/datos/Scripts/Gitea/Project_Euler/src/files/Problem42.txt"
+    words = sort(readdlm(file, ',', String)[:])
+
+    for word in words
+        if word_to_value(word) in triangular_numbers
+            ans += 1
+        end
+    end
+    return ans
+end
+
+
+println("Time to evaluate Problem 42:")
+@btime Problem42()
+println("")
+println("Result for Problem 42: ", Problem42())