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@ -202,7 +202,7 @@ color = np.dtype([("r", np.ubyte),
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`hint:`
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```python
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Z = np.dot(np.ones((5,3)), np.ones((3,2)))
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Z = np.matmul(np.ones((5, 3)), np.ones((3, 2)))
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print(Z)
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# Alternative solution, in Python 3.5 and above
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@ -894,6 +894,32 @@ P0 = np.random.uniform(-10, 10, (10,2))
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P1 = np.random.uniform(-10,10,(10,2))
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p = np.random.uniform(-10, 10, (10,2))
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print(np.array([distance(P0,P1,p_i) for p_i in p]))
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# Author: Yang Wu (Broadcasting)
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def distance_points_to_lines(p: np.ndarray, p_1: np.ndarray, p_2: np.ndarray) -> np.ndarray:
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x_0, y_0 = p.T # Shape -> (n points, )
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x_1, y_1 = p_1.T # Shape -> (n lines, )
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x_2, y_2 = p_2.T # Shape -> (n lines, )
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# Displacement vector coordinates from p_1 -> p_2
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dx = x_2 - x_1 # Shape -> (n lines, )
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dy = y_2 - y_1 # Shape -> (n lines, )
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# The 'cross product' term
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cross_term = x_2 * y_1 - y_2 * x_1 # Shape -> (n lines, )
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# Broadcast x_0, y_0 (n points, 1) and dx, dy, cross_term (1, n lines) -> (n points, n lines)
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numerator = np.abs(
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dy[np.newaxis, :] * x_0[:, np.newaxis]
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- dx[np.newaxis, :] * y_0[:, np.newaxis]
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+ cross_term[np.newaxis, :]
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)
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denominator = np.sqrt(dx**2 + dy**2) # Shape -> (n lines, )
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# Shape (n points, n lines) / (1, n_lines) -> (n points, n lines)
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return numerator / denominator[np.newaxis, :]
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distance_points_to_lines(p, P0, P1)
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```
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#### 80. Consider an arbitrary array, write a function that extract a subpart with a fixed shape and centered on a given element (pad with a `fill` value when necessary) (★★★)
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`hint: minimum maximum`
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@ -202,7 +202,7 @@ color = np.dtype([("r", np.ubyte),
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```python
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Z = np.dot(np.ones((5,3)), np.ones((3,2)))
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Z = np.matmul(np.ones((5, 3)), np.ones((3, 2)))
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print(Z)
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# Alternative solution, in Python 3.5 and above
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@ -894,6 +894,32 @@ P0 = np.random.uniform(-10, 10, (10,2))
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P1 = np.random.uniform(-10,10,(10,2))
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p = np.random.uniform(-10, 10, (10,2))
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print(np.array([distance(P0,P1,p_i) for p_i in p]))
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# Author: Yang Wu (Broadcasting)
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def distance_points_to_lines(p: np.ndarray, p_1: np.ndarray, p_2: np.ndarray) -> np.ndarray:
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x_0, y_0 = p.T # Shape -> (n points, )
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x_1, y_1 = p_1.T # Shape -> (n lines, )
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x_2, y_2 = p_2.T # Shape -> (n lines, )
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# Displacement vector coordinates from p_1 -> p_2
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dx = x_2 - x_1 # Shape -> (n lines, )
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dy = y_2 - y_1 # Shape -> (n lines, )
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# The 'cross product' term
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cross_term = x_2 * y_1 - y_2 * x_1 # Shape -> (n lines, )
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# Broadcast x_0, y_0 (n points, 1) and dx, dy, cross_term (1, n lines) -> (n points, n lines)
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numerator = np.abs(
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dy[np.newaxis, :] * x_0[:, np.newaxis]
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- dx[np.newaxis, :] * y_0[:, np.newaxis]
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+ cross_term[np.newaxis, :]
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)
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denominator = np.sqrt(dx**2 + dy**2) # Shape -> (n lines, )
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# Shape (n points, n lines) / (1, n_lines) -> (n points, n lines)
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return numerator / denominator[np.newaxis, :]
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distance_points_to_lines(p, P0, P1)
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```
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#### 80. Consider an arbitrary array, write a function that extract a subpart with a fixed shape and centered on a given element (pad with a `fill` value when necessary) (★★★)
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@ -2,7 +2,7 @@
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"cells": [
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{
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"cell_type": "markdown",
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"id": "e06c1964",
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"id": "ed5b154a",
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"metadata": {},
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"source": [
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"# 100 numpy exercises\n",
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@ -18,7 +18,7 @@
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},
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{
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"cell_type": "markdown",
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"id": "c108c1c4",
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"id": "f21bc71d",
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"metadata": {},
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"source": [
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"File automatically generated. See the documentation to update questions/answers/hints programmatically."
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@ -26,7 +26,7 @@
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},
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{
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"cell_type": "markdown",
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"id": "2aefe09b",
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"id": "7a3d8374",
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"metadata": {},
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"source": [
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"Run the `initialize.py` module, then call a random question with `pick()` an hint towards its solution with\n",
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@ -36,7 +36,7 @@
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{
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"cell_type": "code",
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"execution_count": null,
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"id": "55c8f855",
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"id": "a3aaf46b",
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"metadata": {},
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"outputs": [],
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"source": [
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@ -46,7 +46,7 @@
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{
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"cell_type": "code",
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"execution_count": null,
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"id": "8f1e8a4a",
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"id": "6db78cf9",
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"metadata": {},
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"outputs": [],
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"source": [
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