automated commit by check50 [check50=True]

8.sql

@@ -3,4 +3,3 @@ SELECT d."name", e."pupils"
 FROM "expenditures" AS e
 JOIN "districts" AS d
 ON e."district_id" = d."id";
--- WHERE d."name" = 'Cambridge';

9.sql

@@ -0,0 +1,8 @@
+-- write a SQL query to find the name (or names) of the school district(s) with the single least number of pupils.
+-- Report only the name(s).
+SELECT d."name"
+FROM "expenditures" AS e
+JOIN "districts" AS d
+ON e."district_id" = d."id"
+ORDER BY "pupils" ASC
+LIMIT 1;