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12.sql

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+-- write a SQL query to find the players among the 10 least expensive players per hit and among the 10 least expensive players per RBI in 2001.
+--     Your query should return a table with two columns, one for the players’ first names and one of their last names.
+--     You can calculate a player’s salary per RBI by dividing their 2001 salary by their number of RBIs in 2001.
+--     You may assume, for simplicity, that a player will only have one salary and one performance in 2001.
+--     Order your results by player ID, least to greatest (or alphabetically by last name, as both are the same in this case!).
+--     Keep in mind the lessons you’ve learned in 10.sql and 11.sql!
+WITH least_expensive_per_hit AS (
+    SELECT
+        p."id",
+        p."first_name",
+        p."last_name"
+    FROM "players" AS p
+    JOIN "salaries" AS s
+        ON s."player_id" = p."id"
+    JOIN "performances" AS perf
+        ON perf."player_id" = p."id"
+       AND perf."year" = s."year"
+    WHERE s."year" = 2001
+      AND perf."H" > 0
+    ORDER BY
+        CAST(s."salary" AS REAL) / perf."H" ASC,
+        p."first_name" ASC,
+        p."last_name" ASC
+    LIMIT 10
+),
+least_expensive_per_rbi AS (
+    SELECT
+        p."id",
+        p."first_name",
+        p."last_name"
+    FROM "players" AS p
+    JOIN "salaries" AS s
+        ON s."player_id" = p."id"
+    JOIN "performances" AS perf
+        ON perf."player_id" = p."id"
+       AND perf."year" = s."year"
+    WHERE s."year" = 2001
+      AND perf."RBI" > 0
+    ORDER BY
+        CAST(s."salary" AS REAL) / perf."RBI" ASC,
+        p."first_name" ASC,
+        p."last_name" ASC
+    LIMIT 10
+)
+SELECT
+    h."first_name",
+    h."last_name"
+FROM least_expensive_per_hit AS h
+JOIN least_expensive_per_rbi AS r
+    ON h."id" = r."id"
+ORDER BY h."id" ASC;