commit 07742617e58cf947dbaad1fb69d809f6896b26a4
Author: bot50 <bot@cs50.harvard.edu>
Date:   Thu Apr 23 14:30:24 2026 +0000

    daviddoji-cs50/problems/2024/sql/dese@20260423T143024.379231471Z

diff --git a/1.sql b/1.sql
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+-- write a SQL query to find the names and cities of all public schools in Massachusetts.
+SELECT "name", "city" FROM "schools" WHERE "type" = "Public School";
diff --git a/10.sql b/10.sql
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diff --git a/11.sql b/11.sql
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diff --git a/12.sql b/12.sql
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diff --git a/13.sql b/13.sql
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diff --git a/2.sql b/2.sql
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+-- write a SQL query to find the names of districts that are no longer operational.
+SELECT "name" FROM "districts" WHERE "name" LIKE "%(non-op)";
diff --git a/3.sql b/3.sql
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+-- write a SQL query to find the average per-pupil expenditure. Name the column “Average District Per-Pupil Expenditure”.
+SELECT AVG("per_pupil_expenditure") AS "Average District Per-Pupil Expenditure" FROM "expenditures";
diff --git a/4.sql b/4.sql
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+-- write a SQL query to find the 10 cities with the most public schools.
+-- Your query should return the names of the cities and the number of public schools within them,
+-- ordered from greatest number of public schools to least. If two cities have the same number of public schools,
+-- order them alphabetically.
+SELECT "city", COUNT(*) AS "Number of schools"
+FROM "schools"
+WHERE "type" = "Public School"
+GROUP BY "city"
+ORDER BY "Number of schools" DESC, "city" ASC
+LIMIT 10;
diff --git a/5.sql b/5.sql
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+-- write a SQL query to find cities with 3 or fewer public schools. Your query should return the names of the cities
+-- and the number of public schools within them, ordered from greatest number of public schools to least.
+-- If two cities have the same number of public schools, order them alphabetically.
+SELECT "city", COUNT(*) AS "Number of schools"
+FROM "schools"
+WHERE "type" = "Public School"
+GROUP BY "city"
+HAVING COUNT(*) <= 3
+ORDER BY "Number of schools" DESC, "city" ASC;
diff --git a/6.sql b/6.sql
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+-- write a SQL query to find the names of schools (public or charter!) that reported a 100% graduation rate.
+SELECT "name"
+FROM "schools"
+WHERE "id" = (
+    SELECT "school_id"
+    FROM "graduation_rates"
+    WHERE "graduated" = 100
+    )
+;
diff --git a/7.sql b/7.sql
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diff --git a/8.sql b/8.sql
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diff --git a/9.sql b/9.sql
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