diff --git a/06-Multivariate-Kalman-Filters.ipynb b/06-Multivariate-Kalman-Filters.ipynb index 566f432..6c888e7 100644 --- a/06-Multivariate-Kalman-Filters.ipynb +++ b/06-Multivariate-Kalman-Filters.ipynb @@ -3149,7 +3149,7 @@ "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython3", - "version": "3.7.4" + "version": "3.8.3" }, "widgets": { "application/vnd.jupyter.widget-state+json": { diff --git a/10-Unscented-Kalman-Filter.ipynb b/10-Unscented-Kalman-Filter.ipynb index 8feb52c..0f41586 100644 --- a/10-Unscented-Kalman-Filter.ipynb +++ b/10-Unscented-Kalman-Filter.ipynb @@ -785,10 +785,10 @@ "\n", "$$ \n", "\\boldsymbol{\\chi}_i = \\begin{cases}\n", - "\\mu + \\left[ \\sqrt{(n+\\lambda)\\Sigma}\\right ]_{i}& \\text{for i=1 .. n} \\\\\n", - "\\mu - \\left[ \\sqrt{(n+\\lambda)\\Sigma}\\right]_{i-n} &\\text{for i=(n+1) .. 2n}\\end{cases}\n", + "\\mu + \\left[ \\sqrt{(n+\\lambda)\\Sigma}\\right ]_{i}& i=1..n \\\\\n", + "\\mu - \\left[ \\sqrt{(n+\\lambda)\\Sigma}\\right]_{i-n} &i=(n+1)..2n\\end{cases}\n", "$$\n", - "The $i$ subscript chooses the i$^{th}$ roth vector of the matrix.\n", + "The $i$ subscript chooses the i$^{th}$ row vector of the matrix.\n", "\n", "In other words, we scale the covariance matrix by a constant, take the square root of it, and ensure symmetry by both adding and subtracting it from the mean. We will discuss how you take the square root of a matrix later.\n", "\n", @@ -1285,7 +1285,7 @@ "cell_type": "markdown", "metadata": {}, "source": [ - "### Tracking Maneuevering Aircraft" + "### Tracking Maneuvering Aircraft" ] }, { @@ -2059,8 +2059,8 @@ "$$\n", "\\begin{cases}\n", "\\mathcal{X}_0 = \\mu \\\\\n", - "\\mathcal{X}_i = \\mu + \\left[\\sqrt{(n+\\lambda)\\Sigma} \\right]_i, & \\texttt{for i=1..n} \\\\\n", - "\\mathcal{X}_i = \\mu - \\left[\\sqrt{(n+\\lambda)\\Sigma}\\right]_{i-n} & \\texttt{for i=(n+1)..2n}\n", + "\\mathcal{X}_i = \\mu + \\left[\\sqrt{(n+\\lambda)\\Sigma} \\right]_i, & i=1..n \\\\\n", + "\\mathcal{X}_i = \\mu - \\left[\\sqrt{(n+\\lambda)\\Sigma}\\right]_{i-n} & i=(n+1)..2n\n", "\\end{cases}\n", "$$\n", "\n", @@ -3250,7 +3250,7 @@ "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython3", - "version": "3.7.4" + "version": "3.8.3" } }, "nbformat": 4,