updates after up
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@@ -556,11 +556,11 @@ To look at the limit in this example, we have (recycling the values in `hs`):
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#| hold: true
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c = 1
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f(x) = x^x
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ys = [(f(c + h) - f(c)) / h for h in hs]
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[hs ys]
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sec_line_slope(h) = (f(c+h) - f(c)) / h
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lim(sec_line_slope, 0)
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```
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The limit looks like $L=1$. A similar check on the left will confirm this numerically.
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The limit looks like $L=1$.
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### Issues with the numeric approach
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