daviddoji/CalculusWithJuliaNotes.jl
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some typos

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This commit is contained in:
Fang Liu
2025-04-22 15:19:44 +08:00
parent 36895faafe
commit ed1d92197a
8 changed files with 20 additions and 20 deletions
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quarto/precalc/functions.qmd
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@@ -1305,7 +1305,7 @@ With this we can answer agequestions, such as:
> How many stars can we see in the sky?
Star [magnitude](https://en.wikipedia.org/wiki/Magnitude_(astronomy)) measures the brightness of celestial objects, with the sun on a log scale so that a magnitude $1$ star is $100$ times brighter than a magnitude $6$ star. The sun has a value around $-27$, Sirius (the brightest visible star) around $-1.46), Venus around $-5$. We will take a magnitude of $6$ or brighter for visibility. (magnitudes less than $6$). The value of $N(6)$ is then
Star [magnitude](https://en.wikipedia.org/wiki/Magnitude_(astronomy)) measures the brightness of celestial objects, with the sun on a log scale so that a magnitude $1$ star is $100$ times brighter than a magnitude $6$ star. The sun has a value around $-27$, Sirius (the brightest visible star) around $-1.46$), Venus around $-5$. We will take a magnitude of $6$ or brighter for visibility. (magnitudes less than $6$). The value of $N(6)$ is then
```{julia}
q(m) = -0.0003*m^3 + 0.0019*m^2 + 0.484*m - 3.82
@@ -1355,7 +1355,7 @@ If a star of magnitude $5$ difference is $100$ times brighter, what is the scale
```{julia}
#| echo: false
explanation = raw"""
The base $a$ solve $\log_a(x + 5) / \log_a(x) = 100$. The logs can be combined and then $a$ can be solved for.
The base $a$ solve $\log_a(100x) - \log_a(x) = 5$. The logs can be combined and then $a$ can be solved for.
"""
choices = [raw"$5$",raw"$\sqrt[5]{100}$", raw"$\sqrt{100}$"]
answer = 2