work on limits section
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@@ -76,6 +76,8 @@ This speaks to continuity at a point, we can extend this to continuity over an i
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Finally, as with limits, it can be convenient to speak of *right* continuity and *left* continuity at a point, where the limit in the definition is replaced by a right or left limit, as appropriate.
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In particular, a function is *continuous* over $[a,b]$ if it is continuous on $(a,b)$, left continuous at $b$ and right continuous at $a$.
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:::{.callout-warning}
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## Warning
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@@ -90,7 +92,7 @@ Most familiar functions are continuous everywhere.
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* For example, a monomial function $f(x) = ax^n$ for non-negative, integer $n$ will be continuous. This is because the limit exists everywhere, the domain of $f$ is all $x$ and there are no jumps.
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* Similarly, the basic trigonometric functions $\sin(x)$, $\cos(x)$ are continuous everywhere.
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* Similarly, the building-block trigonometric functions $\sin(x)$, $\cos(x)$ are continuous everywhere.
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* So are the exponential functions $f(x) = a^x, a > 0$.
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* The hyperbolic sine ($(e^x - e^{-x})/2$) and cosine ($(e^x + e^{-x})/2$) are, as $e^x$ is.
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* The hyperbolic tangent is, as $\cosh(x) > 0$ for all $x$.
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@@ -103,7 +105,7 @@ Some familiar functions are *mostly* continuous but not everywhere.
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* Similarly, $f(x) = \log(x)$ is continuous on $(0,\infty)$, but it is not defined at $x=0$, so is not right continuous at $0$.
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* The tangent function $\tan(x) = \sin(x)/\cos(x)$ is continuous everywhere *except* the points $x$ with $\cos(x) = 0$ ($\pi/2 + k\pi, k$ an integer).
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* The hyperbolic co-tangent is not continuous at $x=0$ – when $\sinh$ is $0$,
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* The semicircle $f(x) = \sqrt{1 - x^2}$ is *continuous* on $(-1, 1)$. It is not continuous at $-1$ and $1$, though it is right continuous at $-1$ and left continuous at $1$.
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* The semicircle $f(x) = \sqrt{1 - x^2}$ is *continuous* on $(-1, 1)$. It is not continuous at $-1$ and $1$, though it is right continuous at $-1$ and left continuous at $1$. (It is continuous on $[-1,1]$.)
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##### Examples of discontinuity
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@@ -210,6 +212,13 @@ solve(del, c)
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This gives the value of $c$.
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This is a bit fussier than need be. As the left and right pieces (say, $f_l$ and $f_r$) as both are polynomials are continuous everywhere, so would have left and right limits given through evaluation. Solving for `c` as follows is enough:
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```{julia}
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solve(ex1(x=>0) ~ ex2(x=>0), c)
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```
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## Rules for continuity
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@@ -384,7 +393,7 @@ numericq(val)
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###### Question
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Suppose $f(x)$, $g(x)$, and $h(x)$ are continuous functions on $(a,b)$. If $a < c < b$, are you sure that $lim_{x \rightarrow c} f(g(x))$ is $f(g(c))$?
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Suppose $f(x)$, $g(x)$, and $h(x)$ are continuous functions on $(a,b)$. If $a < c < b$, are you sure that $\lim_{x \rightarrow c} f(g(x))$ is $f(g(c))$?
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```{julia}
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@@ -453,7 +462,7 @@ yesnoq(true)
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###### Question
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Let $f(x)$ and $g(x)$ be continuous functions whose graph of $[0,1]$ is given by:
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Let $f(x)$ and $g(x)$ be continuous functions. Their graphs over $[0,1]$ are given by:
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```{julia}
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