use quarto, not Pluto to render pages
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@@ -4,7 +4,7 @@
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```julia; echo=false; results="hidden"
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using CalculusWithJulia
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using CalculusWithJulia.WeaveSupport
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const frontmatter = (
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frontmatter = (
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title = "Ranges and Sets",
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description = "Calculus with Julia: Ranges and Sets",
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tags = ["CalculusWithJulia", "precalc", "ranges and sets"],
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@@ -155,7 +155,7 @@ collected to realize the values.
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The number of points is specified with keyword arguments, as in:
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```julia;
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xs = range(-1, 1, length=9) # or simply range(-1, 1, 9)
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xs = range(-1, 1, length=9) # or simply range(-1, 1, 9) as of v"1.7"
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```
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and
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@@ -164,11 +164,9 @@ and
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collect(xs)
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```
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```julia;echo=false
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note("""
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There is also the `LinRange(a, b, n)` function which can be more performant than `range`, as it doesn't try to correct for floating point errors.
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""")
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```
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!!! note
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There is also the `LinRange(a, b, n)` function which can be more performant than `range`, as it doesn't try to correct for floating point errors.
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## Modifying sequences
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@@ -466,8 +464,8 @@ q"1:99",
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q"1:3:99",
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q"1:2:99"
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]
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ans = 3
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radioq(choices, ans)
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answ = 3
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radioq(choices, answ)
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```
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@@ -477,8 +475,8 @@ Which of these will create the sequence $2, 9, 16, 23, \dots, 72$?
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```julia; hold=true;echo=false;
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choices = [q"2:7:72", q"2:9:72", q"2:72", q"72:-7:2"]
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ans = 1
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radioq(choices, ans)
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answ = 1
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radioq(choices, answ)
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```
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@@ -502,8 +500,8 @@ choices = [
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"`1:-1:10`",
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"`1:10`"
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]
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ans = 1
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radioq(choices, ans)
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answ = 1
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radioq(choices, answ)
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```
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###### Question
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@@ -538,8 +536,8 @@ choices = ["It is just random",
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"Addition happens prior to the use of `:` so this is like `1:(4+2):5`",
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"It gives the correct answer, a generator for the vector `[3,5,7,9]`"
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]
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ans = 2
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radioq(choices, ans)
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answ = 2
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radioq(choices, answ)
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```
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###### Question
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@@ -548,8 +546,8 @@ How is `a:b-1` interpreted:
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```julia; hold=true;echo=false;
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choices = ["as `a:(b-1)`", "as `(a:b) - 1`, which is `(a-1):(b-1)`"]
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ans = 1
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radioq(choices, ans)
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answ = 1
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radioq(choices, answ)
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```
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###### Question
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@@ -558,8 +556,8 @@ Create the sequence $10, 100, 1000, \dots, 1,000,000$ using a list comprehension
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```julia; hold=true;echo=false;
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choices = [q"[10^i for i in 1:6]", q"[10^i for i in [10, 100, 1000]]", q"[i^10 for i in [1:6]]"]
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ans = 1
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radioq(choices, ans)
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answ = 1
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radioq(choices, answ)
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```
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###### Question
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@@ -571,8 +569,8 @@ choices = [
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q"[10^-i for i in 1:7]",
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q"[(1/10)^i for i in 1:7]",
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q"[i^(1/10) for i in 1:7]"]
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ans = 2
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radioq(choices, ans)
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answ = 2
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radioq(choices, answ)
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```
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###### Question
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@@ -581,8 +579,8 @@ Evaluate the expression $x^3 - 2x + 3$ for each of the values $-5, -4, \dots, 4,
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```julia; hold=true;echo=false;
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choices = [q"[x^3 - 2x + 3 for i in -5:5]", q"[x^3 - 2x + 3 for x in -(5:5)]", q"[x^3 - 2x + 3 for x in -5:5]"]
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ans = 3
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radioq(choices, ans)
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answ = 3
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radioq(choices, answ)
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```
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###### Question
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