use quarto, not Pluto to render pages

CwJ/limits/limits_extensions.jmd

@@ -149,11 +149,9 @@ limit(f(x), x=>0, dir="+"), limit(f(x), x=>0, dir="-")
 ```
 
 
-```julia; echo=false
-alert("""
-That means the mathematical limit need not exist when `SymPy`'s `limit` returns an answer, as `SymPy` is only carrying out a one sided limit. Explicitly passing `dir="+-"` or checking that both `limit(ex, x=>c)` and `limit(ex, x=>c, dir="-")` are equal would be needed to confirm a limit exists mathematically.
-""")
-```
+!!! warning
+	That means the mathematical limit need not exist when `SymPy`'s `limit` returns an answer, as `SymPy` is only carrying out a one sided limit. Explicitly passing `dir="+-"` or checking that both `limit(ex, x=>c)` and `limit(ex, x=>c, dir="-")` are equal would be needed to confirm a limit exists mathematically.
+
 
 The relation between the two concepts is that a function has a limit at $c$ if
 an only if the left and right limits exist and are equal. This
@@ -623,7 +621,6 @@ The last equality follows, as the function ``x`` dominates the function ``\ln(x)
 
 ## Questions
 
-
 ###### Question
 
 Select the graph for which the limit at ``a`` is infinite.
@@ -761,8 +758,8 @@ Find $\lim_{x \rightarrow 2+} (x-3)/(x-2)$.
 
 ```julia; hold=true; echo=false
 choices=["``L=-\\infty``", "``L=-1``", "``L=0``", "``L=\\infty``"]
-ans = 1
-radioq(choices, ans)
+answ = 1
+radioq(choices, answ)
 ```
 
 Find $\lim_{x \rightarrow -3-} (x-3)/(x+3)$.
@@ -771,8 +768,8 @@ Find $\lim_{x \rightarrow -3-} (x-3)/(x+3)$.
 
 ```julia; hold=true; echo=false
 choices=["``L=-\\infty``", "``L=-1``", "``L=0``", "``L=\\infty``"]
-ans = 4
-radioq(choices, ans)
+answ = 4
+radioq(choices, answ)
 ```
 
 ###### Question
@@ -861,8 +858,8 @@ choices=["The limit does exist - it is any number from -1 to 1",
   "Err, the limit does exists and is 1",
   "The function oscillates too much and its y values do not get close to any one value",
   "Any function that oscillates does not have a limit."]
-ans = 3
-radioq(choices, ans)
+answ = 3
+radioq(choices, answ)
 ```
 
 
@@ -883,8 +880,8 @@ Consider different values of $k$ to see if this limit depends on $k$ or not. Wha
 
 ```julia; hold=true; echo=false
 choices = ["``1``", "``k``", "``\\log(k)``", "The limit does not exist"]
-ans = 1
-radioq(choices, ans)
+answ = 1
+radioq(choices, answ)
 ```
 
 
@@ -908,8 +905,8 @@ Consider different values of $k$ to see if the limit depends on $k$ or not. What
 
 ```julia; hold=true; echo=false
 choices = ["``1``", "``k``", "``\\log(k)``", "The limit does not exist"]
-ans = 2
-radioq(choices, ans)
+answ = 2
+radioq(choices, answ)
 ```
 
 ###### Question
@@ -929,8 +926,8 @@ choices=[
 "the first, second and third ones",
 "the first, second, third, and fourth ones",
 "all of them"]
-ans = 5
-radioq(choices, ans, keep_order=true)
+answ = 5
+radioq(choices, answ, keep_order=true)
 ```
 
 
@@ -947,8 +944,8 @@ L"We can talk about the limit at $\infty$ of $f(x) - mx$ being $b$",
 L"We can say $f(x) - (mx+b)$ has a horizontal asymptote $y=0$",
 L"We can say $f(x) - mx$ has a horizontal asymptote $y=b$",
 "Any of the above"]
-ans = 5
-radioq(choices, ans, keep_order=true)
+answ = 5
+radioq(choices, answ, keep_order=true)
 ```
 
 ###### Question
@@ -976,6 +973,6 @@ choices = [L" $f(x)$ has a limit of $1$ as $x \rightarrow 0$",
 L" $f(x)$ has a limit of $-1$ as $x \rightarrow 0$",
 L" $f(x)$ does not have a limit as $x \rightarrow 0$"
 ]
-ans = 3
-radioq(choices, ans)
+answ = 3
+radioq(choices, answ)
 ```