use quarto, not Pluto to render pages

This commit is contained in:
jverzani
2022-07-24 16:38:24 -04:00
parent 93c993206a
commit 7b37ca828c
879 changed files with 793311 additions and 2678 deletions

View File

@@ -17,7 +17,7 @@ const frontmatter = (
description = "Calculus with Julia: Limits",
tags = ["CalculusWithJulia", "limits", "limits"],
);
const fig_size=(400, 300)
fig_size=(800, 600)
nothing
```
@@ -287,8 +287,9 @@ This progression can be seen to be increasing. Cauchy, in his treatise, can see
```math
\begin{align*}
(1 + \frac{1}{m})^n &= 1 + \frac{1}{1} + \frac{1}{1\cdot 2}(1 = \frac{1}{m}) + \\
& \frac{1}{1\cdot 2\cdot 3}(1 - \frac{1}{m})(1 - \frac{2}{m}) + \cdots +
& \frac{1}{1 \cdot 2 \cdot \cdots \cdot m}(1 - \frac{1}{m}) \cdot \cdots \cdot (1 - \frac{m-1}{m}).
& \frac{1}{1\cdot 2\cdot 3}(1 - \frac{1}{m})(1 - \frac{2}{m}) + \cdots \\
&+
\frac{1}{1 \cdot 2 \cdot \cdots \cdot m}(1 - \frac{1}{m}) \cdot \cdots \cdot (1 - \frac{m-1}{m}).
\end{align*}
```
@@ -1088,8 +1089,8 @@ plot(f, 0,2)
```julia; hold=true; echo=false
ans = 1/4
numericq(ans, 1e-1)
answ = 1/4
numericq(answ, 1e-1)
```
@@ -1158,36 +1159,38 @@ numericq(val, 1e-2)
Select the graph for which there is no limit at ``a``.
```julia; hold=true; echo=false
p1 = plot(;axis=nothing, legend=false)
title!(p1, "(a)")
plot!(p1, x -> x^2, 0, 2, color=:black)
plot!(p1, zero, linestyle=:dash)
annotate!(p1,[(1,0,"a")])
let
p1 = plot(;axis=nothing, legend=false)
title!(p1, "(a)")
plot!(p1, x -> x^2, 0, 2, color=:black)
plot!(p1, zero, linestyle=:dash)
annotate!(p1,[(1,0,"a")])
p2 = plot(;axis=nothing, legend=false)
title!(p2, "(b)")
plot!(p2, x -> 1/(1-x), 0, .95, color=:black)
plot!(p2, x-> -1/(1-x), 1.05, 2, color=:black)
plot!(p2, zero, linestyle=:dash)
annotate!(p2,[(1,0,"a")])
p2 = plot(;axis=nothing, legend=false)
title!(p2, "(b)")
plot!(p2, x -> 1/(1-x), 0, .95, color=:black)
plot!(p2, x-> -1/(1-x), 1.05, 2, color=:black)
plot!(p2, zero, linestyle=:dash)
annotate!(p2,[(1,0,"a")])
p3 = plot(;axis=nothing, legend=false)
title!(p3, "(c)")
plot!(p3, sinpi, 0, 2, color=:black)
plot!(p3, zero, linestyle=:dash)
annotate!(p3,[(1,0,"a")])
p3 = plot(;axis=nothing, legend=false)
title!(p3, "(c)")
plot!(p3, sinpi, 0, 2, color=:black)
plot!(p3, zero, linestyle=:dash)
annotate!(p3,[(1,0,"a")])
p4 = plot(;axis=nothing, legend=false)
title!(p4, "(d)")
plot!(p4, x -> x^x, 0, 2, color=:black)
plot!(p4, zero, linestyle=:dash)
annotate!(p4,[(1,0,"a")])
p4 = plot(;axis=nothing, legend=false)
title!(p4, "(d)")
plot!(p4, x -> x^x, 0, 2, color=:black)
plot!(p4, zero, linestyle=:dash)
annotate!(p4,[(1,0,"a")])
l = @layout[a b; c d]
p = plot(p1, p2, p3, p4, layout=l)
imgfile = tempname() * ".png"
savefig(p, imgfile)
hotspotq(imgfile, (1/2,1), (1/2,1))
l = @layout[a b; c d]
p = plot(p1, p2, p3, p4, layout=l)
imgfile = tempname() * ".png"
savefig(p, imgfile)
hotspotq(imgfile, (1/2,1), (1/2,1))
end
```
###### Question
@@ -1209,8 +1212,8 @@ What is $L$?
```julia; hold=true; echo=false
choices = ["``0``", "``1``", "``e^x``"]
ans = 3
radioq(choices, ans)
answ = 3
radioq(choices, answ)
```
@@ -1237,8 +1240,8 @@ Using the last result, what is the value of $L$?
```julia; hold=true; echo=false
choices = ["``\\cos(x)``", "``\\sin(x)``", "``1``", "``0``", "``\\sin(h)/h``"]
ans = 1
radioq(choices, ans)
answ = 1
radioq(choices, answ)
```
@@ -1309,8 +1312,8 @@ the fact that $x$ is measured in radians. Try to find this limit:
```julia; hold=true; echo=false
choices = [q"0", q"1", q"pi/180", q"180/pi"]
ans = 3
radioq(choices, ans)
answ = 3
radioq(choices, answ)
```
@@ -1318,8 +1321,8 @@ What is the limit `limit(sinpi(x)/x, x => 0)`?
```julia; hold=true; echo=false
choices = [q"0", q"1", q"pi", q"1/pi"]
ans = 3
radioq(choices, ans)
answ = 3
radioq(choices, answ)
```
###### Question: limit properties
@@ -1388,8 +1391,8 @@ choices = [
"Yes, the value is `-11.5123`",
"No, the value heads to negative infinity"
];
ans = 3;
radioq(choices, ans)
answ = 3;
radioq(choices, answ)
```
###### Question
@@ -1433,8 +1436,8 @@ What is `limit(ex, x => 0)`?
```julia; hold=true; echo=false
choices = ["``e^{km}``", "``e^{k/m}``", "``k/m``", "``m/k``", "``0``"]
answer = 1
radioq(choices, answer)
answwer = 1
radioq(choices, answwer)
```
###### Question
@@ -1511,8 +1514,8 @@ between both $g$ and $h$, so must to have a limit of $0$.
""",
L"The functions $g$ and $h$ squeeze each other as $g(x) > h(x)$",
L"The function $f$ has no limit - it oscillates too much near $0$"]
ans = 1
radioq(choices, ans)
answ = 1
radioq(choices, answ)
```
(The [Wikipedia](https://en.wikipedia.org/wiki/Squeeze_theorem) entry for the squeeze theorem has this unverified, but colorful detail: