use quarto, not Pluto to render pages

This commit is contained in:
jverzani
2022-07-24 16:38:24 -04:00
parent 93c993206a
commit 7b37ca828c
879 changed files with 793311 additions and 2678 deletions

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@@ -14,7 +14,7 @@ using Roots
using CalculusWithJulia.WeaveSupport
fig_size = (600, 400)
fig_size = (800, 600)
using Markdown, Mustache
const frontmatter = (
@@ -284,17 +284,13 @@ first $n$ natural numbers.
With this expression, it is readily seen that as $n$ gets large this value gets close to $2/6 = 1/3$.
```julia; echo=false
note("""
!!! note
The above approach, like Archimedes', ends with a limit being
taken. The answer comes from using a limit to add a big number of
small values. As with all limit questions, worrying about whether a
limit exists is fundamental. For this problem, we will see that for
the general statement there is a stretching of the formal concept of a limit.
The above approach, like Archimedes', ends with a limit being
taken. The answer comes from using a limit to add a big number of
small values. As with all limit questions, worrying about whether a
limit exists is fundamental. For this problem, we will see that for
the general statement there is a stretching of the formal concept of a limit.
""")
```
----
@@ -897,17 +893,12 @@ derivative over $[a,b]$. This is significant, the error in $10$ steps
of Simpson's rule is on the scale of the error of $10,000$ steps of
the Riemann sum for well-behaved functions.
```julia; echo=false
note(L"""
The Wikipedia article mentions that Kepler used a similar formula $100$
years prior to Simpson, or about $200$ years before Riemann published
his work. Again, the value in Riemann's work is not the computation of
the answer, but the framework it provides in determining if a function
is Riemann integrable or not.
""")
```
!!! note
The Wikipedia article mentions that Kepler used a similar formula $100$
years prior to Simpson, or about $200$ years before Riemann published
his work. Again, the value in Riemann's work is not the computation of
the answer, but the framework it provides in determining if a function
is Riemann integrable or not.
## Gauss quadrature
@@ -1289,8 +1280,8 @@ choices = [
"``p``",
"``1-p``",
"``p^2``"]
ans = 3
radioq(choices, ans)
answ = 3
radioq(choices, answ)
```
###### Question
@@ -1303,8 +1294,8 @@ choices = [
"``2^5/5 - 0^5/5``",
"``2^4/4 - 0^4/4``",
"``3\\cdot 2^3 - 3 \\cdot 0^3``"]
ans = 2
radioq(choices, ans)
answ = 2
radioq(choices, answ)
```
@@ -1344,8 +1335,8 @@ L"The area between $c$ and $b$ must be positive, so $F(c) < F(b)$.",
"``F(b) - F(c) = F(a).``",
L" $F(x)$ is continuous, so between $a$ and $b$ has an extreme value, which must be at $c$. So $F(c) \geq F(b)$."
]
ans = 1
radioq(choices, ans)
answ = 1
radioq(choices, answ)
```
@@ -1359,8 +1350,8 @@ choices = [
"``10/100``",
"``(10 - 0) \\cdot e^{10} / 100^4``"
]
ans = 1
radioq(choices, ans)
answ = 1
radioq(choices, answ)
```
@@ -1440,9 +1431,11 @@ The area under a curve approximated by a Riemann sum.
#CalculusWithJulia.WeaveSupport.JSXGraph(:integrals, url, caption)
# This is just wrong...
url = "https://raw.githubusercontent.com/jverzani/CalculusWithJulia.jl/master/CwJ/integrals/riemann.js"
url = "./riemann.js"
CalculusWithJulia.WeaveSupport.JSXGraph(url, caption)
```
The interactive graphic shows the area of a right-Riemann sum for different partitions. The function is
```math
@@ -1502,8 +1495,8 @@ L"around $10^{-2}$",
L"around $10^{-4}$",
L"around $10^{-6}$",
L"around $10^{-8}$"]
ans = 4
radioq(choices, ans, keep_order=true)
answ = 4
radioq(choices, answ, keep_order=true)
```
###### Question