daviddoji/CalculusWithJuliaNotes.jl
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use quarto, not Pluto to render pages

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jverzani
2022-07-24 16:38:24 -04:00
parent 93c993206a
commit 7b37ca828c
879 changed files with 793311 additions and 2678 deletions
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26
CwJ/derivatives/related_rates.jmd
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@@ -12,7 +12,7 @@ using SymPy
```julia; echo=false; results="hidden"
using CalculusWithJulia.WeaveSupport
fig_size=(600, 400)
fig_size=(800, 600)
const frontmatter = (
title = "Related rates",
description = "Calculus with Julia: Related rates",
@@ -610,8 +610,8 @@ choices = [
"The rate of change of price will increase",
"The rate of change of price will be positive and will depend on the rate of change of excess demand."
]
ans = 3
radioq(choices, ans, keep_order=true)
answ = 3
radioq(choices, answ, keep_order=true)
```
(Theoretically, when demand exceeds supply, prices increase.)
@@ -625,8 +625,8 @@ choices = [
"If the rate of change of unemployment is negative, the rate of change of wages will be negative.",
"If the rate of change of unemployment is negative, the rate of change of wages will be positive."
]
ans = 2
radioq(choices, ans, keep_order=true)
answ = 2
radioq(choices, answ, keep_order=true)
```
(Colloquially, "the rate of change of unemployment is negative" means the unemployment rate is going down, so there are fewer workers available to fill new jobs.)
@@ -643,8 +643,8 @@ L"The rate of change of pressure is always increasing by $c$",
"If volume is constant, the rate of change of pressure is proportional to the temperature",
"If volume is constant, the rate of change of pressure is proportional to the rate of change of temperature",
"If pressure is held constant, the rate of change of pressure is proportional to the rate of change of temperature"]
ans = 3
radioq(choices, ans, keep_order=true)
answ = 3
radioq(choices, answ, keep_order=true)
```
###### Question
@@ -735,8 +735,8 @@ choices = [
"``f(x) = x``",
"``f(x) = x^2``"
]
ans = 4
radioq(choices, ans, keep_order=true)
answ = 4
radioq(choices, answ, keep_order=true)
```
###### Question
@@ -763,8 +763,8 @@ choices = [
"``y = 1 - \\log(x)``",
"``y = x(2x - 1/x)``"
]
ans = 1
radioq(choices, ans)
answ = 1
radioq(choices, answ)
```
If $dx/dt = -1$, what is $dy/dt$?
@@ -776,6 +776,6 @@ choices = [
"``dy/dt = -2x - 1/x``",
"``dy/dt = 1``"
]
ans=1
radioq(choices, ans)
answ=1
radioq(choices, answ)
```