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@ -495,7 +495,7 @@ We can rearrange $(k(x+h) - k(x))$ as follows:
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\begin{align*}
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\begin{align*}
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(a\cdot f(x+h) + b\cdot g(x+h)) - (a\cdot f(x) + b \cdot g(x)) &=\\
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(a\cdot f(x+h) + b\cdot g(x+h)) - (a\cdot f(x) + b \cdot g(x)) &=\\
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\quada\cdot (f(x+h) - f(x)) + b \cdot (g(x+h) - g(x)). &
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\quad a\cdot (f(x+h) - f(x)) + b \cdot (g(x+h) - g(x)). &
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\end{align*}
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\end{align*}
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$$
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$$
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