work on better figures
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@@ -64,7 +64,88 @@ $$
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#### Examples
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Find the area between
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$$
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\begin{align*}
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f(x) &= \frac{x^3 \cdot (2-x)}{2} \text{ and } \\
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g(x) &= e^{x/3} + (1-\frac{x}{1.7})^6 - 0.6
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\end{align*}
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$$
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over the interval $[0.2, 1.7]$. The area is illustrated in the figure below.
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```{julia}
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f(x) = x^3*(2-x)/2
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g(x) = exp(x/3) + (1 - (x/1.7))^6 - 0.6
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a, b = 0.2, 1.7
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h(x) = g(x) - f(x)
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answer, _ = quadgk(h, a, b)
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answer
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```
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::: {#fig-area-between-f-g}
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```{julia}
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#| echo: false
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p = let
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gr()
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# area between graphs
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# https://github.com/SigurdAngenent/WisconsinCalculus/blob/master/figures/221/09areabetweengraphs.pdf
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f(x) = 1/6+x^3*(2-x)/2
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g(x) = 1/6+exp(x/3)+(1-x/1.7)^6-0.6
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a,b =0.2, 1.7
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A, B = 0, 2
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A′, B′ = A + .1, B - .1
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n = 20
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plot(; empty_style..., aspect_ratio=:equal, xlims=(A,B))
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plot!(f, A′, B′; fn_style...)
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plot!(g, A′, B′; fn_style...)
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xp = range(a, b, n)
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marked = n ÷ 2
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for i in 1:n-1
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x0, x1 = xp[i], xp[i+1]
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mpt = (x0 + x1)/2
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R = Shape([x0,x1,x1,x0], [f(mpt),f(mpt),g(mpt),g(mpt)])
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color = i == marked ? :gray : :white
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plot!(R; fill=(color, 0.5), line=(:black, 1))
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end
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# axis
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plot!([(A,0),(B,0)]; axis_style...)
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# hightlight
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x0, x1 = xp[marked], xp[marked+1]
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_style = (;line=(:gray, 1, :dash))
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plot!([(a,0), (a, f(a))]; _style...)
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plot!([(b,0), (b,f(b))]; _style...)
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plot!([(x0,0), (x0, f(x0))]; _style...)
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plot!([(x1,0), (x1, f(x1))]; _style...)
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annotate!([
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(B′, f(B′), text(L"f(x)", 10, :left,:top)),
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(B′, g(B′), text(L"g(x)", 10, :left, :bottom)),
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(a, 0, text(L"a=x_0", 10, :top, :left)),
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(b, 0, text(L"b=x_n", 10, :top, :left)),
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(x0, 0, text(L"x_i", 10, :top)),
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(x1, 0, text(L"x_{i+1}", 10, :top,:left))
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])
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current()
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end
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plotly()
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p
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```
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Illustration of a Riemann sum approximation to estimate the area between $f(x)$ and $g(x)$ over an interval $[a,b]$. (Figure follows one by @Angenent.)
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:::
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##### Example
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Find the area bounded by the line $y=2x$ and the curve $y=2 - x^2$.
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@@ -970,4 +1051,3 @@ choices = ["The two enclosed areas should be equal",
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"The two enclosed areas are clearly different, as they do not overap"]
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radioq(choices, 1)
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```
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