some typos.

This commit is contained in:
Fang Liu
2025-05-23 16:20:13 +08:00
parent 837a8eb42d
commit 4d0a9e9a72
10 changed files with 54 additions and 60 deletions

View File

@@ -416,7 +416,7 @@ $$
6x - (6y \frac{dy}{dx} \cdot \frac{dy}{dx} + 3y^2 \frac{d^2y}{dx^2}) = 0.
$$
Again, if must be that $d^2y/dx^2$ appears as a linear factor, so we can solve for it:
Again, it must be that $d^2y/dx^2$ appears as a linear factor, so we can solve for it:
$$
@@ -456,7 +456,7 @@ eqn = K(x,y)
eqn1 = eqn(y => u(x))
dydx = solve(diff(eqn1,x), diff(u(x), x))[1] # 1 solution
d2ydx2 = solve(diff(eqn1, x, 2), diff(u(x),x, 2))[1] # 1 solution
eqn2 = d2ydx2(diff(u(x), x) => dydx, u(x) => y)
eqn2 = subs(d2ydx2, diff(u(x), x) => dydx, u(x) => y)
simplify(eqn2)
```
@@ -637,7 +637,7 @@ Okay, now we need to put this value back into our expression for the `x` value a
```{julia}
xstar = N(cps[2](y => ystar, a =>3, b => 3, L => 3))
xstar = N(cps[2](y => ystar, a =>3, b => 3))
```
Our minimum is at `(xstar, ystar)`, as this graphic shows: