align fix; theorem style; condition number

quarto/alternatives/SciML.qmd

@@ -573,13 +573,14 @@ As well, suppose we wanted to parameterize our function and then differentiate.
 
 Consider $d/dp \int_0^\pi \sin(px) dx$. We can do this integral directly to get
 
-
+$$
 \begin{align*}
 \frac{d}{dp} \int_0^\pi \sin(px)dx
 &= \frac{d}{dp}\left( \frac{-1}{p} \cos(px)\Big\rvert_0^\pi\right)\\
 &= \frac{d}{dp}\left( -\frac{\cos(p\cdot\pi)-1}{p}\right)\\
 &= \frac{\cos(p\cdot \pi) - 1}{p^2} + \frac{\pi\cdot\sin(p\cdot\pi)}{p}
 \end{align*}
+$$
 
 Using `Integrals` with `QuadGK` we have: