# --- Day 1: Report Repair ---

# After saving Christmas five years in a row, you've decided to take a vacation
# at a nice resort on a tropical island. Surely, Christmas will go on without you.

# The tropical island has its own currency and is entirely cash-only. The gold
# coins used there have a little picture of a starfish; the locals just call
# them stars. None of the currency exchanges seem to have heard of them, but
# somehow, you'll need to find fifty of these coins by the time you arrive so
# you can pay the deposit on your room.

# To save your vacation, you need to get all fifty stars by December 25th.

# Collect stars by solving puzzles. Two puzzles will be made available on each
# day in the Advent calendar; the second puzzle is unlocked when you complete
# the first. Each puzzle grants one star. Good luck!

# Before you leave, the Elves in accounting just need you to fix your expense
# report (your puzzle input); apparently, something isn't quite adding up.

# Specifically, they need you to find the two entries that sum to 2020 and then
# multiply those two numbers together.

# For example, suppose your expense report contained the following:

# 1721
# 979
# 366
# 299
# 675
# 1456

# In this list, the two entries that sum to 2020 are 1721 and 299. Multiplying
# them together produces 1721 * 299 = 514579, so the correct answer is 514579.

# Of course, your expense report is much larger. Find the two entries that sum
# to 2020; what do you get if you multiply them together?

with open("files/P1.txt", "r") as f:
    numbers = [int(number) for number in f.read().strip().split("\n")]


def part_1() -> None:
    for n in numbers:
        for i in range(len(numbers)):
            if n + numbers[i] == 2020:
                print(f"{n} times {numbers[i]} is {n*numbers[i]}")
                break
        else:
            continue
        break


# --- Part Two ---

# The Elves in accounting are thankful for your help; one of them even offers
# you a starfish coin they had left over from a past vacation. They offer you
# a second one if you can find three numbers in your expense report that meet
# the same criteria.

# Using the above example again, the three entries that sum to 2020 are 979,
# 366, and 675. Multiplying them together produces the answer, 241861950.

# In your expense report, what is the product of the three entries that sum to
# 2020?


def part_2() -> None:
    for n in numbers:
        for i in range(len(numbers)):
            for j in range(len(numbers)):
                if n + numbers[i] + numbers[j] == 2020:
                    print(
                        f"{n} times {numbers[i]} times {numbers[j]} is "
                        f"{n*numbers[i]*numbers[j]}"
                    )
                    break
            else:
                continue
            break
        else:
            continue
        break


if __name__ == "__main__":
    part_1()
    part_2()