# --- Day 4: Giant Squid --- # You're already almost 1.5km (almost a mile) below the surface of the ocean, # already so deep that you can't see any sunlight. What you can see, however, # is a giant squid that has attached itself to the outside of your submarine. # Maybe it wants to play bingo? # Bingo is played on a set of boards each consisting of a 5x5 grid of numbers. # Numbers are chosen at random, and the chosen number is marked on all boards # on which it appears. (Numbers may not appear on all boards.) If all numbers # in any row or any column of a board are marked, that board wins. (Diagonals # don't count.) # The submarine has a bingo subsystem to help passengers (currently, you and # the giant squid) pass the time. It automatically generates a random order in # which to draw numbers and a random set of boards (your puzzle input). For # example: # 7,4,9,5,11,17,23,2,0,14,21,24,10,16,13,6,15,25,12,22,18,20,8,19,3,26,1 # 22 13 17 11 0 # 8 2 23 4 24 # 21 9 14 16 7 # 6 10 3 18 5 # 1 12 20 15 19 # 3 15 0 2 22 # 9 18 13 17 5 # 19 8 7 25 23 # 20 11 10 24 4 # 14 21 16 12 6 # 14 21 17 24 4 # 10 16 15 9 19 # 18 8 23 26 20 # 22 11 13 6 5 # 2 0 12 3 7 # After the first five numbers are drawn (7, 4, 9, 5, and 11), there are no # winners, but the boards are marked as follows (shown here adjacent to each # other to save space): # 22 13 17 11 0 3 15 0 2 22 14 21 17 24 4 # 8 2 23 4 24 9 18 13 17 5 10 16 15 9 19 # 21 9 14 16 7 19 8 7 25 23 18 8 23 26 20 # 6 10 3 18 5 20 11 10 24 4 22 11 13 6 5 # 1 12 20 15 19 14 21 16 12 6 2 0 12 3 7 # After the next six numbers are drawn (17, 23, 2, 0, 14, and 21), there are # still no winners: # 22 13 17 11 0 3 15 0 2 22 14 21 17 24 4 # 8 2 23 4 24 9 18 13 17 5 10 16 15 9 19 # 21 9 14 16 7 19 8 7 25 23 18 8 23 26 20 # 6 10 3 18 5 20 11 10 24 4 22 11 13 6 5 # 1 12 20 15 19 14 21 16 12 6 2 0 12 3 7 # Finally, 24 is drawn: # 22 13 17 11 0 3 15 0 2 22 14 21 17 24 4 # 8 2 23 4 24 9 18 13 17 5 10 16 15 9 19 # 21 9 14 16 7 19 8 7 25 23 18 8 23 26 20 # 6 10 3 18 5 20 11 10 24 4 22 11 13 6 5 # 1 12 20 15 19 14 21 16 12 6 2 0 12 3 7 # At this point, the third board wins because it has at least one complete row # or column of marked numbers (in this case, the entire top row is marked: # 14 21 17 24 4). # The score of the winning board can now be calculated. Start by finding the # sum of all unmarked numbers on that board; in this case, the sum is 188. # Then, multiply that sum by the number that was just called when the board # won, 24, to get the final score, 188 * 24 = 4512. # To guarantee victory against the giant squid, figure out which board will win # first. What will your final score be if you choose that board? import queue from typing import Tuple with open("files/P4.txt", "r") as f: data = [line for line in f.read().strip().split("\n\n")] numbers, all_boards = data[0].split(","), [ board.split("\n") for board in data[1:] ] def _boards(lst: list[str]) -> list[Tuple[str, ...]]: return [tuple(tup.split()) for tup in lst] def sum_board(board: list[Tuple[str, ...]], lst: list[str]) -> int: return sum( int(number) for row in board for number in row if number not in lst ) def has_won(board: list[Tuple[str, ...]], lst: list[str]) -> bool: for row in board: winner = all(num in lst for num in row) if winner: return winner for col in range(5): winner = all(num in lst for num in [row[col] for row in board]) if winner: return winner return False boards = [_boards(board) for board in all_boards] def part_1() -> None: numbers_drawn = [] for number in numbers: numbers_drawn.append(number) if len(numbers_drawn) < 5: continue for board in boards: if has_won(board, numbers_drawn): return print(sum_board(board, numbers_drawn) * int(number)) # --- Part Two --- # On the other hand, it might be wise to try a different strategy: let the # giant squid win. # You aren't sure how many bingo boards a giant squid could play at once, so # rather than waste time counting its arms, the safe thing to do is to figure # out which board will win last and choose that one. That way, no matter which # boards it picks, it will win for sure. # In the above example, the second board is the last to win, which happens # after 13 is eventually called and its middle column is completely marked. If # you were to keep playing until this point, the second board would have a sum # of unmarked numbers equal to 148 for a final score of 148 * 13 = 1924. # Figure out which board will win last. Once it wins, what would its final # score be? def part_2() -> None: numbers_drawn = [] winner = False while not winner: for number in numbers: numbers_drawn.append(number) if len(numbers_drawn) < 5: continue idx = 0 while idx < len(boards): if has_won(boards[idx], numbers_drawn): if len(boards) > 1: boards.pop(idx) else: return print( sum_board(boards[idx], numbers_drawn) * int(number) ) else: idx += 1 if __name__ == "__main__": part_1() part_2()