Solution to problem 15 in Python
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src/Year_2021/P15.py
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src/Year_2021/P15.py
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# --- Day 15: Chiton ---
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# You've almost reached the exit of the cave, but the walls are getting closer
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# together. Your submarine can barely still fit, though; the main problem is
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# that the walls of the cave are covered in chitons, and it would be best not to
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# bump any of them.
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# The cavern is large, but has a very low ceiling, restricting your motion to
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# two dimensions. The shape of the cavern resembles a square; a quick scan of
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# chiton density produces a map of risk level throughout the cave (your puzzle
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# input). For example:
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# 1163751742
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# 1381373672
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# 2136511328
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# 3694931569
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# 7463417111
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# 1319128137
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# 1359912421
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# 3125421639
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# 1293138521
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# 2311944581
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# You start in the top left position, your destination is the bottom right
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# position, and you cannot move diagonally. The number at each position is its
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# risk level; to determine the total risk of an entire path, add up the risk
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# levels of each position you enter (that is, don't count the risk level of your
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# starting position unless you enter it; leaving it adds no risk to your total).
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# Your goal is to find a path with the lowest total risk. In this example, a
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# path with the lowest total risk is highlighted here:
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# 1163751742
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# 1381373672
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# 2136511328
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# 3694931569
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# 7463417111
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# 1319128137
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# 1359912421
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# 3125421639
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# 1293138521
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# 2311944581
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# The total risk of this path is 40 (the starting position is never entered, so
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# its risk is not counted).
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# What is the lowest total risk of any path from the top left to the bottom
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# right?
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import heapq
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with open("files/P15.txt") as f:
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grid = {
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(x, y): int(n)
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for y, row in enumerate(f.read().split("\n"))
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for x, n in enumerate(row)
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}
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max_x, max_y = max(grid)
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def get_value(pos, width, height):
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# Calculate additional components for the value
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x_component = pos[0] // width
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y_component = pos[1] // height
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current_value = grid[pos[0] % width, pos[1] % height]
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combined_value = current_value + x_component + y_component
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if combined_value < 10:
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return combined_value
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else:
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return combined_value % 9
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def bfs(width, height, scale):
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queue, visited = [(0, 0, 0)], {(0, 0)}
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while queue:
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risk, x, y = heapq.heappop(queue)
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# Check if we reached the target coordinates
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if (x, y) == (width * scale - 1, height * scale - 1):
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return risk
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for neighb in ((x + 1, y), (x, y + 1), (x - 1, y), (x, y - 1)):
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if neighb in visited:
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continue
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if (
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0 <= neighb[0] < width * scale
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and 0 <= neighb[1] < height * scale
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):
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new_risk = risk + get_value(neighb, width, height)
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visited.add(neighb)
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heapq.heappush(queue, (new_risk, *neighb))
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def part1():
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res = bfs(max_x + 1, max_y + 1, scale=1)
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print(f"The lowest total risk is {res}")
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# --- Part Two ---
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# Now that you know how to find low-risk paths in the cave, you can try to find
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# your way out.
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# The entire cave is actually five times larger in both dimensions than you
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# thought; the area you originally scanned is just one tile in a 5x5 tile area
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# that forms the full map. Your original map tile repeats to the right and
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# downward; each time the tile repeats to the right or downward, all of its risk
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# levels are 1 higher than the tile immediately up or left of it. However, risk
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# levels above 9 wrap back around to 1. So, if your original map had some
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# position with a risk level of 8, then that same position on each of the 25
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# total tiles would be as follows:
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# 8 9 1 2 3
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# 9 1 2 3 4
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# 1 2 3 4 5
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# 2 3 4 5 6
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# 3 4 5 6 7
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# Each single digit above corresponds to the example position with a value of 8
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# on the top-left tile. Because the full map is actually five times larger in
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# both dimensions, that position appears a total of 25 times, once in each
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# duplicated tile, with the values shown above.
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# Here is the full five-times-as-large version of the first example above, with
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# the original map in the top left corner highlighted:
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# 11637517422274862853338597396444961841755517295286
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# 13813736722492484783351359589446246169155735727126
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# 21365113283247622439435873354154698446526571955763
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# 36949315694715142671582625378269373648937148475914
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# 13191281372421239248353234135946434524615754563572
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# 13599124212461123532357223464346833457545794456865
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# 31254216394236532741534764385264587549637569865174
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# 12931385212314249632342535174345364628545647573965
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# 23119445813422155692453326671356443778246755488935
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# 22748628533385973964449618417555172952866628316397
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# 24924847833513595894462461691557357271266846838237
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# 32476224394358733541546984465265719557637682166874
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# 47151426715826253782693736489371484759148259586125
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# 85745282229685639333179674144428178525553928963666
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# 42365327415347643852645875496375698651748671976285
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# 23142496323425351743453646285456475739656758684176
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# 34221556924533266713564437782467554889357866599146
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# 43587335415469844652657195576376821668748793277985
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# 45332667135644377824675548893578665991468977611257
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# 46246169155735727126684683823779579493488168151459
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# 54698446526571955763768216687487932779859814388196
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# 69373648937148475914825958612593616972361472718347
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# 46434524615754563572686567468379767857948187896815
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# 46833457545794456865681556797679266781878137789298
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# 64587549637569865174867197628597821873961893298417
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# 45364628545647573965675868417678697952878971816398
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# 56443778246755488935786659914689776112579188722368
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# 57357271266846838237795794934881681514599279262561
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# 65719557637682166874879327798598143881961925499217
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# 71484759148259586125936169723614727183472583829458
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# 67554889357866599146897761125791887223681299833479
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# Equipped with the full map, you can now find a path from the top left corner
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# to the bottom right corner with the lowest total risk:
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# 11637517422274862853338597396444961841755517295286
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# 13813736722492484783351359589446246169155735727126
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# 21365113283247622439435873354154698446526571955763
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# 36949315694715142671582625378269373648937148475914
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# 13599124212461123532357223464346833457545794456865
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# 23119445813422155692453326671356443778246755488935
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# 45364628545647573965675868417678697952878971816398
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# 56443778246755488935786659914689776112579188722368
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# 57357271266846838237795794934881681514599279262561
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# 71484759148259586125936169723614727183472583829458
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# 28178525553928963666413917477752412858886352396999
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# 57545635726865674683797678579481878968159298917926
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# 75698651748671976285978218739618932984172914319528
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# 56475739656758684176786979528789718163989182927419
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# 67554889357866599146897761125791887223681299833479
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# The total risk of this path is 315 (the starting position is still never
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# entered, so its risk is not counted).
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# Using the full map, what is the lowest total risk of any path from the top
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# left to the bottom right?
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def part2():
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res = bfs(max_x + 1, max_y + 1, 5)
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print(f"The lowest total risk is {res}")
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if __name__ == "__main__":
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part1()
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part2()
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