Solution to problem 8 in Python

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David Doblas Jiménez 2022-04-05 11:47:08 +02:00
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# --- Day 8: I Heard You Like Registers ---
# You receive a signal directly from the CPU. Because of your recent assistance
# with jump instructions, it would like you to compute the result of a series
# of unusual register instructions.
# Each instruction consists of several parts: the register to modify, whether
# to increase or decrease that register's value, the amount by which to
# increase or decrease it, and a condition. If the condition fails, skip the
# instruction without modifying the register. The registers all start at 0. The
# instructions look like this:
# b inc 5 if a > 1
# a inc 1 if b < 5
# c dec -10 if a >= 1
# c inc -20 if c == 10
# These instructions would be processed as follows:
# Because a starts at 0, it is not greater than 1, and so b is not
# modified.
# a is increased by 1 (to 1) because b is less than 5 (it is 0).
# c is decreased by -10 (to 10) because a is now greater than or equal to 1
# (it is 1).
# c is increased by -20 (to -10) because c is equal to 10.
# After this process, the largest value in any register is 1.
# You might also encounter <= (less than or equal to) or != (not equal to).
# However, the CPU doesn't have the bandwidth to tell you what all the
# registers are named, and leaves that to you to determine.
# What is the largest value in any register after completing the instructions
# in your puzzle input?
from collections import defaultdict from collections import defaultdict
from typing import Dict
with open("files/P8.txt") as f: with open("files/P8.txt") as f:
instructions = [line for line in f.read().strip().split("\n")] instructions = [line for line in f.read().strip().split("\n")]
# print(instructions)
registry: dict[str, int] = defaultdict(int) def inc(s: str, dic: Dict[str, int]) -> None:
def inc(s: str) -> None:
reg, inst, num, iff, reg_cond, op, num_cond = s.split() reg, inst, num, iff, reg_cond, op, num_cond = s.split()
if eval("registry[reg_cond] " + op + num_cond): if eval("dic[reg_cond] " + op + num_cond):
registry[reg] += int(num) dic[reg] += int(num)
for instruction in instructions: def dec(s: str, dic: Dict[str, int]) -> None:
inc(instruction) reg, inst, num, iff, reg_cond, op, num_cond = s.split()
break if eval("dic[reg_cond] " + op + num_cond):
dic[reg] -= int(num)
print(registry)
def part_1() -> None:
registry: Dict[str, int] = defaultdict(int)
for instruction in instructions:
if "inc" in instruction:
inc(instruction, registry)
elif "dec" in instruction:
dec(instruction, registry)
val = max(registry.values())
print(f"The largest value in the registry is {val}")
# --- Part Two ---
# To be safe, the CPU also needs to know the highest value held in any register
# during this process so that it can decide how much memory to allocate to
# these operations. For example, in the above instructions, the highest value
# ever held was 10 (in register c after the third instruction was evaluated).
def part_2() -> None:
registry: Dict[str, int] = defaultdict(int)
max_val = 0
for instruction in instructions:
if "inc" in instruction:
inc(instruction, registry)
elif "dec" in instruction:
dec(instruction, registry)
max_val = max(max_val, max(registry.values()))
print(f"The largest value ever held by the registry is {max_val}")
if __name__ == "__main__":
part_1()
part_2()